Suppose you are incharge of rationing in a State affected by food shortage.The following rëports arrive from your local investigators :Daily calorie value of food available per adult during current period:AreaMeanStandard Deviation2,500500Y2,200300The estimated requirement of an adult is taken at 3,000 calories daily and the absoluteminimum at 1250. Comment on the reported figure and determine which in your opinion needsmore urgent attention.

We have to find which of the area need more attention:

Answered: Suppose you are incharge of rationing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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To determine if their 14 oz filling machine is properly adjusted, Harvey Soft Drinks has decided to use an X-Chart which uses the range to estimate the variability in the sample. J. Answer How to enter your answ Table Step 1 of 7: What is the Center Line of the control chart? Round your answer to three decimal places. Control Chart Period 1 2 3 4 5 6 7 8 9 10 11 Select the Copy Table button to copy all values. To select an entire row or column, either click on the row or column header or use the Shift and arrow keys. To find the average of the selected cells, select the Average Values button. Copy Table Average Values The average of the selected cell(s) is 14.000. Copy Value Sample Mean Sample Range 14.0060 0.04 0.04 0.04 0.10 0.08 0.09 0.07 0.05 0.05 0.06 0.07 obs1 obs2 obs3 obs4 obs5 14.00 13.99 14.03 14.01 14.00 14.02 14.05 14.05 14.01 14.04 14.0340 14.02 14.01 14.05 14.04 14.02 14.0280 14.04 13.97 14.05 13.95 14.00 14.0020 13.96 14.01 14.00 14.04 14.02 14.0060 13.96 14.00 14.00…
A quantitative data set of size 60 has mean 50 and standard deviation 66. Approximately how many observations lie between 44 and 56?
age 2 of 6 b. should not be rejected. c. should be revised. 70°F Sunny d. should not be tested. ANSWER: b MSC 600 Quantitative Methods 7. Part of an ANOVA table is shown below. Source of Variation Between Treatments Within Treatments (Error) TOTAL 480 18 The mean square due to treatments (MSTR) is a. 20. b. 60. c. 18 d. 15. ANSWER: b 8. Part of an ANOVA table is shown below. Source of Sum of Variation "Squares Between Treatments 180 Within Treatments (Error) TOTAL 1105 words Sum of Degrees of SquaresFreedom 180 3 480 The mean square due to error (MSE) is a. 60. b. 15. c. 18. d. 20 ANSWER: 4 W Text Predictions: On Degrees of Freedom 3 18 Mean Square Mean Square Focus 32 F F 00 O Search LAH COLLEGE OF BUSINESS J 7 10 Re SAMSU
The data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.025 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions? : Click the icon to view the data. What are the hypotheses for this test? Data Table O A. Ho: H1 = H2 =H3 H: At least one of the means is different from the others. Туре с O B. Ho: H1 # H2 * H3 Туре А 6.2 Type B 8.2 7.7 Hyi Hy = H2 =H3 5.8 7.3 7.6 6.2 8.4 8.8 OC. Ho: H1 = H2 = H3 H: H1 # H2 #H3 5.7 7.8 8.8 6.9 8.8 9.3 6.1 7.7 8.1 O D. Ho: At least one of the means is different from the others. 7.9 5.7 7.3 5.9 7.3 7.8 H: H1 =H2 = H3 5.6 8.1 5.6 Determine the test statistic. F = (Round to two decimal places as needed.) Print Done Identify the P-value. Click to select your answer(s).…
Reports on a student's test score such as the SAT or a child's height or weight usually give the percentile as well as the actual value of the variable. The percentile is just the cumulative proportion stated as a percent: the percent of all values of the variable that were lower than this one. The upper arm lengths of females in the United States are approximately Normal with mean 35.735.7 cm and standard deviation 2.12.1 cm, and those for males are approximately Normal with mean 39.139.1 and standard deviation 2.32.3 cm. Larry, a 6060‑year‑old male in the United States, has a upper arm length of 37.837.8 cm. What is his percentile? (Enter your answer rounded to two decimal places.)
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2. Is the data in the frequency table below Nominal, Interval, or Ordinal level of measurement? Lunch Choices Mac 'n Cheese Sandwich Chicken Nuggets Answer: Soup Hamburger Answer: Frequency 5 8 6 2 1 3. What is the mode of the frequency table in question 2?
Q.No.3: Discuss different scales for the measurement of data with two examples
iDENTIFY THE TYPE AND LEVEL OF MEASUREMENT OF THE FOLLOWING VARIABLES gender - either male or female runtime - time to run 1.5 miles (in min) age - age of the gym member in years weight - weight of the gym member (in kg) oxygen consumption - measure of the ability to use oxygen in the blood stream (in ml/min) rest pulse - resting pulse rate (in bpm) maximum pulse - maximum pulse rate during the run (in bpm)
4..Solve the problem using anova
What is the appropriate measure of center for these data? O A. Mode OB. Range OC. Mean O D. Median O E. Skew 1525 54 1 5 2 6 5 4 3 19 8 7 6 4 4345656 7 6 9

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