Suppose you are given the following five pairs of scores: X Y 4 2 1 3 4 4 2 6 9 10 Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid. 012345678910109876543210yx Based on your scatter diagram, you would expect the correlation to be ___ . (positive??) The mean x score is MXX = , and the mean y score is MYY = Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations Squared Deviations Products X Y X – MXX Y – MYY (X – MXX)² (Y – MYY)² (X – MXX)(Y – MYY) 4 2 1 3 4 4 2 6 9 10 The sum of squares for x is SSxx = . The sum of squares for y is SSyy = . The sum of products is SP = Because the sign of the sum of products is _ (neg or pos), the sign of the correlation coefficient __ (depends on the signs of SSx and SSy, will be neg or will be pos . The correlation coefficient is r = _ . Look at your scatter diagram again. If you excluded the point (9, 10), you would expect the recalculated correlation coefficient to be (diff or similiar) , because __ (x and y are correlated, (9, 10) is an outlier, the relationshiop between x and y is nonlinear or correlation is not the same as the causation)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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4. Scatter plots and calculating correlation

Suppose you are given the following five pairs of scores:

X	Y
4	2
1	3
4	4
2	6
9	10

Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right corner of the tool, and drag it to the appropriate location on the grid.

012345678910109876543210yx

Based on your scatter diagram, you would expect the correlation to be _____ . (positive??)

The mean x score is MXX =

, and the mean y score is MYY =

Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations.

Scores	Deviations	Squared Deviations	Products
X	Y	X – MXX	Y – MYY	(X – MXX)²	(Y – MYY)²	(X – MXX)(Y – MYY)
4	2
1	3
4	4
2	6
9	10

The sum of squares for x is SSxx =

. The sum of squares for y is SSyy =

. The sum of products is SP =

Because the sign of the sum of products is _____ (neg or pos), the sign of the correlation coefficient ______ (depends on the signs of SSx and SSy, will be neg or will be pos .

The correlation coefficient is r = _____ .

Look at your scatter diagram again. If you excluded the point (9, 10), you would expect the recalculated correlation coefficient to be ______ (diff or similiar) , because ______ (x and y are correlated, (9, 10) is an outlier, the relationshiop between x and y is nonlinear or correlation is not the same as the causation).

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