Suppose y is implicitly defined as a function of x by the equations below. Find the slope of the tangent line at the point (1, 1). (a) 6xvy - y? = 5/x dy dx (b) 2 + ye' = 2x + e* dy dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
Suppose \( y \) is implicitly defined as a function of \( x \) by the equations below. Find the slope of the tangent line at the point \( (1, 1) \).

(a) \[ 6x\sqrt{y} - y^2 = 5\sqrt{x} \]

\[ \frac{dy}{dx} = \text{\_\_\_\_\_\_\_} \]

(b) \[ 2 + ye^y = 2x + e^x \]

\[ \frac{dy}{dx} = \text{\_\_\_\_\_\_\_} \]
Transcribed Image Text:Suppose \( y \) is implicitly defined as a function of \( x \) by the equations below. Find the slope of the tangent line at the point \( (1, 1) \). (a) \[ 6x\sqrt{y} - y^2 = 5\sqrt{x} \] \[ \frac{dy}{dx} = \text{\_\_\_\_\_\_\_} \] (b) \[ 2 + ye^y = 2x + e^x \] \[ \frac{dy}{dx} = \text{\_\_\_\_\_\_\_} \]
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