Suppose y = C₁ cosh(kx) + C₂ sinh(kx) where k> 0 is a constant, and C₁ and C₂ are arbitrary constants. Find the following. Enter C₁ as "C1" and C2 as "C2". dy help (formulas) dx d²y dx² help (formulas) Rewrite your answer to the previous part in terms of y. d²y help (formulas) dx² Find the general solution to d²y dx² = 49y. Enter your answer as an equation y =?.

Q: 2xy+X=0

A: In the question it is asked to solve the differential equation given, dxdy-2xy+x=0.

Q: 6r - 5r

A: We use exponent and multiplication.

Q: Garaph the equation ri 2+2coso

A: The graph shape is cardioid

Q: dx 16x4 – 1

A:

Q: 3x-y x-3y 6x 6x Simplify

A: A detailed solution is given below.

Q: arctan(-1)

A:

Q: x + x2 = 0

A:

Q: Multiply. (-x+6)?=

A: (a+b)2=a2+b2+2ab

Q: + 4 Y

A: Graph the line equation

Q: Simplify the expression.

A: Here we have to Simplify the expression. A=(2x3y)2(3x-1y2)

Q: 5 x²ỹ+ 3xỹ + 5y = In (x)

A: Solution

Q: X+2y=3 , x-y=6

A:

Q: 1 [² [²" - dydz dr I

A:

Q: dt t2-t-6

A:

Q: TC 3X-X²

A:

Q: I need the answer as soon as possible

A: Solve the given problem.

Q: h 25 5e-X VI-25e-2x

A:

Q: 1-0 1-V

A: The given function for integration is,

Q: 5x - 3y = 18 3x + 3y = 30

A: From the given problem:   5x-3y=18 ....13x+3y=30.....(2)   Now adding the equation (1) & (2).…

Q: 40 (3x +10)°

A: Using concept of opposite Angles.

Q: 3-3+1=?

A: NOTE As you don't mention what to find. I am just simplify the expression.

Q: dx 1+ 2x + 2x²+2x²tx4

A:

Q: where din you get 2y

A:

Q: V6x + 7 – 2 = x

A:

Q: What is the value of X? _  and  Y? _

A: Given, 6x-3y=9 -8x+5y=-11

Q: 7x4 28x7

A: Given that,       7x428x7 = 14x3     (By exponent rule    xmxn=xm-n)

Q: . csc* (Inx²) 2 7.

A:

Q: Question: diagonalize, -1 0-1 0 0 -1 2 1 2

A:

Q: Multiply. (-x+3)23= D

A: To multiply  (-x+3)²

Q: Hi the solution is in

A: Given claim: Test whether the true mean age of the store's shoppers is over 21. Null Hypothesis:…

Q: S- 3+ Vx

A:

Q: What are variables in algebra ?

A: What are variables in algebra ?

Q: simplify z-6z

A: