Suppose x has a distribution with μ = 24 and a = 20. USE SALT (a) If a random sample of size n = 48 is drawn, find μ, ox and P(24 ≤ x ≤ 26). (Round a to two decimal places and the probability to four decimal places.) x = 0x = P(24 ≤x≤ 26) = (b) If a random sample of size n = 74 is drawn, find ux, x and P(24 ≤ x ≤ 26). (Round a to two decimal places and the probability to four decimal places.) fx = o x = P(24 ≤ x ≤ 26) = (c) Why should you expect the probability..af. part. (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).) The standard deviation of part (b) is --Select--- ✓part (a) because of the ---Select-- sample size. Therefore, the distribution about u is --Select--

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Suppose x has a distribution with = 24 and σ = 20.
USE SALT
MY NOTES
(a) If a random sample of size n = 48 is drawn, find , oxand P(24≤ x ≤ 26). (Round a to two decimal places and the probability to four decimal places.)
Hx=
0x =
P(24≤ x ≤ 26) =
(b) If a random sample of size n = 74 is drawn, find , ax and P(24≤ x ≤ 26). (Round a to two decimal places and the probability to four decimal places.)
fx =
0x =
P(24≤ x ≤26) =
(c) Why should you expect the probability..of. part.(b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).)
The standard deviation of part (b) is --Select--- ✓part (a) because of the --Select--sample size. Therefore, the distribution about is ---Select--
Transcribed Image Text:Suppose x has a distribution with = 24 and σ = 20. USE SALT MY NOTES (a) If a random sample of size n = 48 is drawn, find , oxand P(24≤ x ≤ 26). (Round a to two decimal places and the probability to four decimal places.) Hx= 0x = P(24≤ x ≤ 26) = (b) If a random sample of size n = 74 is drawn, find , ax and P(24≤ x ≤ 26). (Round a to two decimal places and the probability to four decimal places.) fx = 0x = P(24≤ x ≤26) = (c) Why should you expect the probability..of. part.(b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).) The standard deviation of part (b) is --Select--- ✓part (a) because of the --Select--sample size. Therefore, the distribution about is ---Select--
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