Suppose x has a distribution with a mean of 70 and a standard deviation of 52. Random samples of size n = 64 are drawn.(a) Describe the x distribution and compute the mean and standard deviation of the distribution.x has --Select-.+ distribution with mean u,and standard deviation o, =(b) Find the z value corresponding to x = 57.(c) Find P(x < 57). (Round your answer to four decimal places.)P(X < 57) =(d) Would it be unusual for a random sample of size 64 from the x distribution to have a sample mean less than 57? Explain.No, it would not be unusual because more than 5% of all such samples have means less than 57.No, it would not be unusual because less than 5% of all such samples have means less than 57.Yes, it would be unusual because more than 5% of all such samples have means less than 57.Yes, it would be unusual because less than 5% of all such samples have means less than 57.

Answered: Image /qna-images/answer/1d39381c-f407-4d5f-841d-2fed25f3a65c.jpg

Answered: Suppose x has a distribution with a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 15 days. Let X be the length of a randomly recorded pregnancy in the village. What is the distribution of X? X ~ N (,) Please show the following answers to 4 decimal places. If a pregnancy randomly chosen in the village, find the probability that it lasted less than 244 days. If a pregnancy randomly chosen in the village, find the probability that it lasted between 290 and 298 days. Please show the following answer to a whole day. The 72nd percentile pregnancy length in this village is ___________ days.
A large group of students took a test in Physics and the final grades have a mean of 70 and a standard deviation of 10. The passing score is 60. The distribution is approximately normal. Using the 68-95-99.7 (empirical) rule, find the percentage of the students(a) scored between 60 and 80.(b) scored between 50 and 90.(c) higher than 80. (d) should pass the test.
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7. If you made only n = 1 measurement of rack height, the standard deviation of 41 measurement would be (a) zero, because there is no difference between the value and the average. (b) Equal to the measured value. (c) Undetermined, because you need more measurements to find a standard deviation (d) Infinite because the denominator (n – 1) is zero.
Today, the waves are crashing onto the beach every 5.1 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.1 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 1.4 seconds after the person arrives is P(x = 1.4) = The probability that the wave will crash onto the beach between 1.3 and 4.7 seconds after the person arrives is P(1.3 < x < 4.7) = The probability that it will take longer than 3.92 seconds for the wave to crash onto the beach after the person arrives is P(x > 3.92) = Suppose that the person has already been standing at the shoreline for 1.1 seconds without a wave crashing in. Find the probability that it will take between 2.4 and 3.8 seconds for the wave to crash onto the shoreline. 84% of the time a person will wait at least how long before the wave crashes in?…
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1/ The patient recovery time from a particular surgical procedure is normally distributed with a mean of 4 days and a standard deviation of 2 days. Let X be the recovery time for a randomly selected patient. Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(,)b. What is the median recovery time? daysc. What is the Z-score for a patient that took 5.1 days to recover? d. What is the probability of spending more than 4.8 days in recovery? e. What is the probability of spending between 3.5 and 4.1 days in recovery? f. The 90th percentile for recovery times is days. 2/The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 79 minutes and a standard deviation of 15 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(,)b. Find the…
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