Suppose we titrate 20.0 mL of 0.100 M HCHO2 (Ka = 1.8 × 10–4) with 0.100 M NaOH. Calculate the pH. After a total of 15.0 mL of base has been added: pH = Please only answer the incorrect question, thank you so much!
Suppose we titrate 20.0 mL of 0.100 M HCHO2 (Ka = 1.8 × 10–4) with 0.100 M NaOH. Calculate the pH. After a total of 15.0 mL of base has been added: pH = Please only answer the incorrect question, thank you so much!
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Suppose we titrate 20.0 mL of 0.100 M HCHO2 (Ka = 1.8 × 10–4) with 0.100 M NaOH. Calculate the pH.
After a total of 15.0 mL of base has been added: pH =
Please only answer the incorrect question, thank you so much!
![Suppose we titrate 20.0 ml of 0.100 M HCHO2 (K, - 1.8 x 10-4) with 0.100 M NAOH. Calculate the pH.
Your answer is correct.
Before any base is added:
pH =
2,37
Hint
Your answer is correct.
When half of the HCHO2 has been neutralized:
pH =
3.74
Hint
* Your answer is incorrect.
After a total of 15.0 mL of base has been added:
pH =
i
1,54
Hint
Assistance Used
Recall the relationship between K, and HCHO2, CH02.
Your answer is correct.
At the equivalence point:
pH =
8.22
Hint](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ad36720-6101-4e4b-abcd-9f36fc84b0e9%2F66550af7-9f76-42f5-85f6-e72f39f20ba3%2F5904rr_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose we titrate 20.0 ml of 0.100 M HCHO2 (K, - 1.8 x 10-4) with 0.100 M NAOH. Calculate the pH.
Your answer is correct.
Before any base is added:
pH =
2,37
Hint
Your answer is correct.
When half of the HCHO2 has been neutralized:
pH =
3.74
Hint
* Your answer is incorrect.
After a total of 15.0 mL of base has been added:
pH =
i
1,54
Hint
Assistance Used
Recall the relationship between K, and HCHO2, CH02.
Your answer is correct.
At the equivalence point:
pH =
8.22
Hint
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