Suppose we have the following recurrence: S(0) = 1 S(1) = 1
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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discrete structure
![Suppose we have the following recurrence:
S(0) = 1
S(1) = 1
S(n) = 2S(n/2) +1
Which of the following statements is true?
O
a) T(n) = 0(n)
O b) T(n) = 2(n)
O c) T(n) = O(n)
d) T(n)=6n-5 for n > 1
O e) T(n)=2n-1 n > 1
f) T(n)=3n-2 n > 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F03c6967c-58df-4789-89c0-8a0967e3d455%2F22c25c36-8682-4f3c-bede-157cb8d8748b%2Fjcfxzl_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose we have the following recurrence:
S(0) = 1
S(1) = 1
S(n) = 2S(n/2) +1
Which of the following statements is true?
O
a) T(n) = 0(n)
O b) T(n) = 2(n)
O c) T(n) = O(n)
d) T(n)=6n-5 for n > 1
O e) T(n)=2n-1 n > 1
f) T(n)=3n-2 n > 1
![Which of the following recurrence relations are O(n)?
You may assume n is a power of 2.
О a) Т(п) — 2T(n/2) + п, T(1) %3D 1
O b) T(n) = 2T(n/2) + 1, T(1) = 1
О) T(п) — 2T (n/2) + 1, Т(1) —D п
2T(n/2) + 1, T(1) = n
O d) T(n) = T(n – 1) + 1, T(1) = 1
%3D
O e) T(n) = T(n – 1) + n, T(1) = 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F03c6967c-58df-4789-89c0-8a0967e3d455%2F22c25c36-8682-4f3c-bede-157cb8d8748b%2Fbuqupv5_processed.png&w=3840&q=75)
Transcribed Image Text:Which of the following recurrence relations are O(n)?
You may assume n is a power of 2.
О a) Т(п) — 2T(n/2) + п, T(1) %3D 1
O b) T(n) = 2T(n/2) + 1, T(1) = 1
О) T(п) — 2T (n/2) + 1, Т(1) —D п
2T(n/2) + 1, T(1) = n
O d) T(n) = T(n – 1) + 1, T(1) = 1
%3D
O e) T(n) = T(n – 1) + n, T(1) = 1
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