Suppose we have the following C function: long stir (long x) { if (x <= 1) { return 1; } // we're not concerned about small values long result = 0; if (x & 1) { result = x + 5; } else { result = x / 2; // if x is odd } return result; In the assembly implementation of the function below, fill in the three missing jump instructions so that it matches the code above: stir: cmpg $1, trdi labell movą $1, trax retą # return 1 labell: xorg trax, trax # result = 0 testg $1, trdi label2 movą šrdi, trax addą $5, $rax * result x + 5 label3 label2: movą trdi, trax shlq $1, trax * result = x / 2 label3: retą

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### C Function and Assembly Translation

#### C Function

```c
long stir(long x) {
    if (x <= 1) { return 1; }  // we're not concerned about small values

    long result = 0;
    if (x & 1) {               // if x is odd
        result = x + 5;
    } else {
        result = x / 2;
    }
    return result;
}
```

#### Assembly Implementation

The task is to fill in the three missing jump instructions in the assembly code to match the C function above.

```assembly
stir:
    cmpq $1, %rdi                 
    <missing jump>                # fill this to direct the flow to either label1 or next line
    movq $1, %rax                 # return 1
    retq 
label1:
    xorq %rax, %rax               # result = 0
    testq $1, %rdi
    <missing jump>                # fill this based on whether x is odd
    movq %rdi, %rax
    addq $5, %rax                 # result = x + 5
    <missing jump>                # fill this to skip the next block of code 
label2:
    movq %rdi, %rax
    shrq $1, %rax                 # result = x / 2
label3:
    retq
```

### Explanation

The C function `stir` takes a long integer `x` and returns:

- `1` if `x` is less than or equal to `1`.
- `x + 5` if `x` is odd.
- `x / 2` if `x` is even.

The assembly code follows the same logic. The missing jump instructions need to properly direct the control flow:

- **First missing jump**: If `x` is greater than `1`, jump to `label1` to continue the logic for handling odd or even values.
  
- **Second missing jump**: After checking if `x` is odd with `testq`, jump to `label2` if `x` is not odd (i.e., when even).

- **Third missing jump**: After executing the `x + 5` addition logic, jump to `label3` to return the correct result, bypassing the division logic.
Transcribed Image Text:### C Function and Assembly Translation #### C Function ```c long stir(long x) { if (x <= 1) { return 1; } // we're not concerned about small values long result = 0; if (x & 1) { // if x is odd result = x + 5; } else { result = x / 2; } return result; } ``` #### Assembly Implementation The task is to fill in the three missing jump instructions in the assembly code to match the C function above. ```assembly stir: cmpq $1, %rdi <missing jump> # fill this to direct the flow to either label1 or next line movq $1, %rax # return 1 retq label1: xorq %rax, %rax # result = 0 testq $1, %rdi <missing jump> # fill this based on whether x is odd movq %rdi, %rax addq $5, %rax # result = x + 5 <missing jump> # fill this to skip the next block of code label2: movq %rdi, %rax shrq $1, %rax # result = x / 2 label3: retq ``` ### Explanation The C function `stir` takes a long integer `x` and returns: - `1` if `x` is less than or equal to `1`. - `x + 5` if `x` is odd. - `x / 2` if `x` is even. The assembly code follows the same logic. The missing jump instructions need to properly direct the control flow: - **First missing jump**: If `x` is greater than `1`, jump to `label1` to continue the logic for handling odd or even values. - **Second missing jump**: After checking if `x` is odd with `testq`, jump to `label2` if `x` is not odd (i.e., when even). - **Third missing jump**: After executing the `x + 5` addition logic, jump to `label3` to return the correct result, bypassing the division logic.
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