Suppose we have a solid mixture represented by point k. How much of the solid in the photo below is in equilibrium per kg of pure B? Given the Txy diagram below of a two-component (A and B) solid-liquid system.
Suppose we have a solid mixture represented by point k. How much of the solid in the photo below is in equilibrium per kg of pure B? Given the Txy diagram below of a two-component (A and B) solid-liquid system.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Suppose we have a solid mixture represented by point k. How much of the solid in the photo below is in equilibrium per kg of pure B?
Given the Txy diagram below of a two-component (A and B) solid-liquid system.

Transcribed Image Text:b
0.2
0.4
0.6
0.8
1
Mole fraction of B, xa
Temperature, T
0.16
0.23
0.57
0.67
0.84

Transcribed Image Text:%3D
A Mole fiaction of B = 0.67
Mole fraction of A = 9
Mole fiaction of A+ Mole faaction B=1
Mole fyaction of A= 1-O. 67
Mole feiaction of A= 0-333
v If we have a i mole of A and 2 mole of B.
we have mole fraction 0-333 and 0.67.
Total mole of A and B= 3
Mole fraction of A= 1
3
Mole faactiion of A=0.333
Mole fHaction of B= 2
Mole faaction of B=0.67
So, the chemical tosemula Ax By
= A1B2 on AB2
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