Suppose we have a deck of cards, but some of the cards are missing. That is, instead of 52 cards, we have 48 cards. My friend wants to play a magic trick - he wants me to pick a card, remember it, put it back in the deck, then shuffle the deck. He claims he can find that card. Clearly, my friend keeps track of my card somehow, but if he did not keep track, and the cards were perfectly randomized, what would be the probability that he would select my card from the deck? Round your answer to 4 decimal places. Recall Canvas truncates trailing Os automatically without loss of marks - that means if you enter something like 0.5000, Canvas changes it to 0.5, and you do not lose marks as a result.
Suppose we have a deck of cards, but some of the cards are missing. That is, instead of 52 cards, we have 48 cards. My friend wants to play a magic trick - he wants me to pick a card, remember it, put it back in the deck, then shuffle the deck. He claims he can find that card. Clearly, my friend keeps track of my card somehow, but if he did not keep track, and the cards were perfectly randomized, what would be the probability that he would select my card from the deck? Round your answer to 4 decimal places. Recall Canvas truncates trailing Os automatically without loss of marks - that means if you enter something like 0.5000, Canvas changes it to 0.5, and you do not lose marks as a result.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![Suppose we have a deck of cards, but some of the cards are missing. That is, instead of 52 cards,
we have 48 cards. My friend wants to play a magic trick - he wants me to pick a card, remember it,
put it back in the deck, then shuffle the deck. He claims he can find that card. Clearly, my friend
keeps track of my card somehow, but if he did not keep track, and the cards were perfectly
randomized, what would be the probability that he would select my card from the deck? Round
your answer to 4 decimal places. Recall Canvas truncates trailing Os automatically without loss of
marks - that means if you enter something like 0.5000, Canvas changes it to 0.5, and you do not
lose marks as a result.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad61951d-78a6-4370-af39-8d7818cfc65e%2F9efb2071-2a0a-4646-abe6-b8f6908482f1%2Ft783xm_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose we have a deck of cards, but some of the cards are missing. That is, instead of 52 cards,
we have 48 cards. My friend wants to play a magic trick - he wants me to pick a card, remember it,
put it back in the deck, then shuffle the deck. He claims he can find that card. Clearly, my friend
keeps track of my card somehow, but if he did not keep track, and the cards were perfectly
randomized, what would be the probability that he would select my card from the deck? Round
your answer to 4 decimal places. Recall Canvas truncates trailing Os automatically without loss of
marks - that means if you enter something like 0.5000, Canvas changes it to 0.5, and you do not
lose marks as a result.
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