Suppose we are given the following data set with sample standard deviations, sd₁ = 0.2377, sd₂ = 0.1162, sd3 = 0.1473, 84 = 0.2136 and Q-Q plot: 80 02 Sample Quantiles 0.0 -0.1 0.1 -0.2 со Normal Q-Q Plot Theoretical Quantiles Type 1 Type 2 Type 3 Type 4 3.83 4.09 4.41 4.14 4.7 4.52 4.79 4.61 4.37 4.41 4.27 4.08 4.98 5.46 5.05 5.22 (a) Verify that it is appropriate to carry out a one-way ANOVA with this data set. (b) Do the following results of the one-way ANOVA suggest that at least two of the true treatment means differ at a significance level of a = 0.05? Explain. of Sum Sq Mean Sq F value Pr (>F) treatment 3 2.6525 0.8842 25.76 0.0000163 *** Residuals 12 0.4119 0.0343 signif. codes: 0***** 0.001 0.01 0.05 0.11 (c) Use the following output to perform Tukey's procedure (a = 0.05). Tukey multiple comparisons of means 95% family-wise confidence level Fit: aov (formula = measurement treatment, data = data) Streatment diff Tur upr p adj type2-type1 0.5375 0.1485452 0.92645485 0.0069138 type 3-type1 0.1650 -0.2239548 0.55395485 0.6036475 type4-typel 1.0600 0.6710452 1.44895485 0.0000174 type 3-type2 -0.3725 -0.7614548 0.01645485 0.0620474 type4-type2 0.5225 0.1335452 0.91145485 0.0084319 type4-type3 0.8950 0.5060452 1.28395485 0.0000931
Suppose we are given the following data set with sample standard deviations, sd₁ = 0.2377, sd₂ = 0.1162, sd3 = 0.1473, 84 = 0.2136 and Q-Q plot: 80 02 Sample Quantiles 0.0 -0.1 0.1 -0.2 со Normal Q-Q Plot Theoretical Quantiles Type 1 Type 2 Type 3 Type 4 3.83 4.09 4.41 4.14 4.7 4.52 4.79 4.61 4.37 4.41 4.27 4.08 4.98 5.46 5.05 5.22 (a) Verify that it is appropriate to carry out a one-way ANOVA with this data set. (b) Do the following results of the one-way ANOVA suggest that at least two of the true treatment means differ at a significance level of a = 0.05? Explain. of Sum Sq Mean Sq F value Pr (>F) treatment 3 2.6525 0.8842 25.76 0.0000163 *** Residuals 12 0.4119 0.0343 signif. codes: 0***** 0.001 0.01 0.05 0.11 (c) Use the following output to perform Tukey's procedure (a = 0.05). Tukey multiple comparisons of means 95% family-wise confidence level Fit: aov (formula = measurement treatment, data = data) Streatment diff Tur upr p adj type2-type1 0.5375 0.1485452 0.92645485 0.0069138 type 3-type1 0.1650 -0.2239548 0.55395485 0.6036475 type4-typel 1.0600 0.6710452 1.44895485 0.0000174 type 3-type2 -0.3725 -0.7614548 0.01645485 0.0620474 type4-type2 0.5225 0.1335452 0.91145485 0.0084319 type4-type3 0.8950 0.5060452 1.28395485 0.0000931
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:Q7.
Suppose we are given the following data set with sample standard deviations, sd₁
84 = 0.2136 and Q-Q plot:
Sample Quantiles
0.3
0.2
0.1
0.0
-0.1
-0.2
20
-2
-1
Normal Q-Q Plot
0
Theoretical Quantiles
Streatment
Type 1
Type 2
Type 3
Type 4
2
Df Sum Sq Mean Sq F value
Pr (>F)
treatment
3 2.6525 0.8842 25.76 0.0000163 ***
Residuals 12 0.4119 0.0343
signif. codes: 00.001 '**' 0.01 0.05.¹0.11
4.09 4.41 4.14 3.83
4.7 4.52 4.79 4.61
4.37 4.41 4.27 4.08
4.98 5.46 5.05
5.22
(a) Verify that it is appropriate to carry out a one-way ANOVA with this data set.
(b) Do the following results of the one-way ANOVA suggest that at least two of the true treatment means differ at a
significance level of a = 0.05? Explain.
(c) Use the following output to perform Tukey's procedure (a
=
Tukey multiple comparisons of means
95% family-wise confidence level
Fit: aov (formula = measurement treatment, data = data)
diff
1wr
upr p adj
type 2-type1 0.5375 0.1485452 0.92645485 0.0069138
type 3-type1 0.1650 -0.2239548 0.55395485 0.6036475
type4-typel 1.0600 0.6710452 1.44895485 0.0000174
type3-type2 -0.3725 -0.7614548 0.01645485 0.0620474
type4-type2 0.5225 0.1335452 0.91145485 0.0084319
type4-type3 0.8950 0.5060452 1.28395485 0.0000931
0.2377, sd₂ = 0.1162, sd3 =
0.05).
0.1473,
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