Suppose V is a vector space of finite dimension k and T : V → V is a linear transformation. Suppose T has one single eigenvalue λER, and call n its geometric multiplicity. Which value(s) of n (if any) will result in [T]% being similar to a diagonal matrix, for all bases a of V? Your "values" of n should be in terms of k. If no such value of n exists, explain why not. Clarification 1: In general there are two meanings of multiplicity that apply to eigenvalues. "Multiplicity of an eigenvalue" could mean "number of times (x - 2) appears in the characteristic polynomial x(x) ("Algebraic Multiplicity") or the dimension of the eigenspace E₁ ("Geometric Multiplicity"). In this question, we are considering the \textbf{geometric multiplicity} n of λ. Clarification 2: Saying "There exists basis a of V for which [T] is diagonal" is equivalent to saying that "[T] is similar to a diagonal matrix for all bases a of V". Hint: Your solution can consider k>n, k = n, and k < n separately.
