Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)-that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). 3 4 5 6 7 8 9 10 11 12 13 14 15 procedure main() a: integer: 1 b:integer:=2 procedure middle() end b:integer:=a procedure inner () print a,b end a:integer: 3 inner() print a,b end middle() print a, b Consider declaration order. Consider only the C and Modula-3 sets of rules.
Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)-that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). 3 4 5 6 7 8 9 10 11 12 13 14 15 procedure main() a: integer: 1 b:integer:=2 procedure middle() end b:integer:=a procedure inner () print a,b end a:integer: 3 inner() print a,b end middle() print a, b Consider declaration order. Consider only the C and Modula-3 sets of rules.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Only C and Modula-3 outputs with explanation

Transcribed Image Text:question 3.5, page 167.
Suppose this was code for a language with the declaration-order rules of C
(but with nested subroutines)-that is, names must be declared before use,
and the scope of a name extends from its declaration through the end of
the block. At each print statement, indicate which declarations of a and b
are in the referencing environment. What does the program print (or will
the compiler identify static semantic errors)? Repeat the exercise for the
declaration-order rules of C# (names must be declared before use, but the
scope of a name is the entire block in which it is declared) and of Modula-3
(names can be declared in any order, and their scope is the entire block in
which they are declared).
1
2
3
5
6
7
8
9
10
11
12
13
14
15
procedure main()
a: integer :=1
b:integer:=2
procedure middle ()
end
b:integer :=a
procedure inner ()
print a, b
end
a: integer :=3
inner ()
print a,b
end
middle ()
print a, b
Consider declaration order. Consider only the C and Modula-3 sets of rules.
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