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Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)-that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). 3 4 5 6 7 8 9 10 11 12 13 14 15 procedure main() a: integer: 1 b:integer:=2 procedure middle() end b:integer:=a procedure inner () print a,b end a:integer: 3 inner() print a,b end middle() print a, b Consider declaration order. Consider only the C and Modula-3 sets of rules.

Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)-that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). 3 4 5 6 7 8 9 10 11 12 13 14 15 procedure main() a: integer: 1 b:integer:=2 procedure middle() end b:integer:=a procedure inner () print a,b end a:integer: 3 inner() print a,b end middle() print a, b Consider declaration order. Consider only the C and Modula-3 sets of rules.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Only C and Modula-3 outputs with explanation

question 3.5, page 167. Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)-that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). 1 2 3 5 6 7 8 9 10 11 12 13 14 15 procedure main() a: integer :=1 b:integer:=2 procedure middle () end b:integer :=a procedure inner () print a, b end a: integer :=3 inner () print a,b end middle () print a, b Consider declaration order. Consider only the C and Modula-3 sets of rules.
Transcribed Image Text:question 3.5, page 167. Suppose this was code for a language with the declaration-order rules of C (but with nested subroutines)-that is, names must be declared before use, and the scope of a name extends from its declaration through the end of the block. At each print statement, indicate which declarations of a and b are in the referencing environment. What does the program print (or will the compiler identify static semantic errors)? Repeat the exercise for the declaration-order rules of C# (names must be declared before use, but the scope of a name is the entire block in which it is declared) and of Modula-3 (names can be declared in any order, and their scope is the entire block in which they are declared). 1 2 3 5 6 7 8 9 10 11 12 13 14 15 procedure main() a: integer :=1 b:integer:=2 procedure middle () end b:integer :=a procedure inner () print a, b end a: integer :=3 inner () print a,b end middle () print a, b Consider declaration order. Consider only the C and Modula-3 sets of rules.
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