Suppose there was a release of 0.572 mole of particle A and 0.792 mole of particle B and both particles are accelerated to 5.73 MeV. What is the energy in terms of kJ/mole for both particles A and B? Hint: 1 MeV = 1 x 106 eV and 1 eV = 1.602 X 10-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogrado's number of particles which is 6.02214 x 1023 particles/mole. 210 83BI 210 84P0 and then A + 210 206 13 84PO 82PB → B ++ O 3.852 x 10-15 kJ / particle O 3.194 x 1015 kJ / particle 3.669 x 10-15 kJ / particle O 1.742 x 10-15 kJ / particle O 2.764 x 10-15 kJ / particle 4.021 x 1015 kJ / particle O 2.527 x 10-15 kJ / particle

Suppose there was a release of 0.572 mole of particle A and 0.792 mole of particle B and both particles are accelerated to 5.73 MeV. What is the energy in terms of kJ/mole for both particles A and B? Hint: 1 MeV = 1 x 106 eV and 1 eV = 1.602 X 10-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogrado's number of particles which is 6.02214 x 1023 particles/mole. 210 83BI 210 84P0 and then A + 210 206 13 84PO 82PB → B ++ O 3.852 x 10-15 kJ / particle O 3.194 x 1015 kJ / particle 3.669 x 10-15 kJ / particle O 1.742 x 10-15 kJ / particle O 2.764 x 10-15 kJ / particle 4.021 x 1015 kJ / particle O 2.527 x 10-15 kJ / particle

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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