Suppose the true proportion of voters in the county who support a specific candidate is 0.58. Consider th sampling distribution for the proportion of supporters with sample size n 197. What is the mean of this distribution? What is the standard deviation of this distribution?
Suppose the true proportion of voters in the county who support a specific candidate is 0.58. Consider th sampling distribution for the proportion of supporters with sample size n 197. What is the mean of this distribution? What is the standard deviation of this distribution?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Sampling Distribution of Proportions
**Scenario:**
Suppose the true proportion of voters in the county who support a specific candidate is 0.58. Consider the sampling distribution for the proportion of supporters with a sample size \( n = 197 \).
**Questions:**
1. **What is the mean of this distribution?**
- [Input box for the answer]
2. **What is the standard deviation of this distribution?**
- [Input box for the answer]
**Instructions:**
Please answer the questions based on the given scenario. When you're ready, click the "Submit Question" button below.
[Button: Submit Question]
---
**Explanation:**
**The Mean of the Sampling Distribution:**
The mean of the sampling distribution (also called the expected value) for the proportion is equal to the true proportion of the population. Therefore, if the true proportion \( p \) is 0.58, the mean \( \mu \) is also 0.58.
**The Standard Deviation of the Sampling Distribution:**
The standard deviation of a proportion in a sampling distribution can be calculated using the formula:
\[ \sigma = \sqrt{\frac{p(1-p)}{n}} \]
where \( p \) is the true proportion (0.58 in this case) and \( n \) is the sample size (197 here).
By inserting the values into the formula:
\[ \sigma = \sqrt{\frac{0.58(1-0.58)}{197}} \]
Calculating this will give the standard deviation of the sampling distribution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fae9dff02-6614-4387-a434-63ee01638e81%2F9012f8c9-6671-4f89-b0ee-4da6cf37d0b1%2F7ygl9un_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Sampling Distribution of Proportions
**Scenario:**
Suppose the true proportion of voters in the county who support a specific candidate is 0.58. Consider the sampling distribution for the proportion of supporters with a sample size \( n = 197 \).
**Questions:**
1. **What is the mean of this distribution?**
- [Input box for the answer]
2. **What is the standard deviation of this distribution?**
- [Input box for the answer]
**Instructions:**
Please answer the questions based on the given scenario. When you're ready, click the "Submit Question" button below.
[Button: Submit Question]
---
**Explanation:**
**The Mean of the Sampling Distribution:**
The mean of the sampling distribution (also called the expected value) for the proportion is equal to the true proportion of the population. Therefore, if the true proportion \( p \) is 0.58, the mean \( \mu \) is also 0.58.
**The Standard Deviation of the Sampling Distribution:**
The standard deviation of a proportion in a sampling distribution can be calculated using the formula:
\[ \sigma = \sqrt{\frac{p(1-p)}{n}} \]
where \( p \) is the true proportion (0.58 in this case) and \( n \) is the sample size (197 here).
By inserting the values into the formula:
\[ \sigma = \sqrt{\frac{0.58(1-0.58)}{197}} \]
Calculating this will give the standard deviation of the sampling distribution.
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