Suppose the slope of the tangent line at any point on a curve is curve passes thru (1,3), approximate the tangent line at (1.2, y(1.2)). x²+4y (a) y = 0.301193x + 2.96745 (b) y = 0.03193x + 2.69745 (c) y = 0.03193x + 2.96745 (d) y = 0.30193x + 2.69745 If the

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Q: Find an equation of the tangent line to the curve y = 5 – 2x – 3x² at (1,0). y =

A: We will find the equation of the tangent line to the curve at the given point as following.

Q: If the Suppose the slope of the tangent line at any point on a curve is x2+4y² curve passes thru…

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Q: Find an equation of the tangent line to the graph of the function y=xex-ex

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Q: The slope of the tangent line to the graph of the function y = 8Vx – 3 at (9, 21) is %3D 1.33 -2.33…

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Q: Find the tangent to y = ((x+ 1)/ (x- 2))? at x = 3. |(Type an equation.)

A: Given y=((x+1)/(x-2))^(2) We have to find tangent line as shown below  We know that equation of line…

Q: Find the slope of the tangent line to the graph at the given point. 4xcosy +1 = 5 at the point (2,)

A: Solve, as follows: 4xcosy+1=541cosy+x-sinydydx=0dydx=cosyxsiny

Q: Do curve sketching of-  xy=( x2  -9)2

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