Suppose the ski patrol raises a rescue sled and victim, having a total mass of 85.0 kg, up a  ? = 56.0°  slope at constant speed, as shown in the figure. DO NOT USE THE ANGLE SHOWN IN THE FIGURE! USE THE ANGLE IN THE PROBLEM STATEMENT ABOVE. The coefficient of friction between the sled and the snow is 0.140. (a) Calculate the normal force on the sled (in N).  N (b) Calculate the work done (in J) by the force of friction as the sled moves 30.0 m up the hill. (Hint: Think about the direction of the friction force. Should it be different than the direction shown in the figure?).  J (c) Calculate the work done (in J) by the tension force in the rope on the sled over this distance.

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Suppose the ski patrol raises a rescue sled and victim, having a total mass of 85.0 kg, up a 
? = 56.0°
 slope at constant speed, as shown in the figure. DO NOT USE THE ANGLE SHOWN IN THE FIGURE! USE THE ANGLE IN THE PROBLEM STATEMENT ABOVE.
The coefficient of friction between the sled and the snow is 0.140.
(a)
Calculate the normal force on the sled (in N).
 N
(b)
Calculate the work done (in J) by the force of friction as the sled moves 30.0 m up the hill. (Hint: Think about the direction of the friction force. Should it be different than the direction shown in the figure?).
 J
(c)
Calculate the work done (in J) by the tension force in the rope on the sled over this distance.
 J
(d)
Calculate the work done (in J) done by the force of gravity on the sled over this distance.
 J
The image illustrates the forces acting on a person being evacuated on a stretcher up an inclined plane, which is at a 60-degree angle to the horizontal. 

1. **Forces:**
   - **Tension (T):** This force is directed along the rope, pulling the stretcher upwards along the incline.
   - **Friction (f):** This force opposes motion and acts parallel to the inclined surface, directed downwards along the incline.
   - **Weight (w):** This force acts vertically downward, representing the gravitational force on the person and the stretcher.

2. **Incline:**
   - The angle of the incline is 60 degrees, indicating a steep slope.

This setup is often used for analyzing the components of forces on an inclined plane in physics, demonstrating concepts such as tension, friction, gravitational force, and vector components of forces.
Transcribed Image Text:The image illustrates the forces acting on a person being evacuated on a stretcher up an inclined plane, which is at a 60-degree angle to the horizontal. 1. **Forces:** - **Tension (T):** This force is directed along the rope, pulling the stretcher upwards along the incline. - **Friction (f):** This force opposes motion and acts parallel to the inclined surface, directed downwards along the incline. - **Weight (w):** This force acts vertically downward, representing the gravitational force on the person and the stretcher. 2. **Incline:** - The angle of the incline is 60 degrees, indicating a steep slope. This setup is often used for analyzing the components of forces on an inclined plane in physics, demonstrating concepts such as tension, friction, gravitational force, and vector components of forces.
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