Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 92.9 kg, down a theta= 79.4º slope at constant acceleration a=-1.7 m/s2, as shown in Figure (here we assume the positive direction is going down the slope. So the given acceleration is a negative value, it means its direction is going up the slope, slowing down as it moving downward). So The coefficient of friction between the sled and the snow is 0.100. How many Joules of work is done by the tension in the rope as the sled moves 9.1 m along the hill? Use g= 10 m/s2. Your answer for this problem maybe some large number. Just put in the raw number as your answer. For example, 34567.11. But remember you have to specify if the work is positive or negative, if it is negative, you need to input, for example, -34567.11

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows: