Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 72.0 kg, down a theta= 51.6° slope at constant acceleration a=-2.5 m/s², as shown in Figure (here we assume the positive direction is going down the slope. So the given acceleration is a negative value, it means its direction is going up the slope, slowing down as it moving downward). So The coefficient of friction between the sled and the snow is 0.100. How many Joules of work is done by the tension in the rope as the sled moves 2.6 m along the hill? Use g= 10 m/s². Your answer for this problem maybe some large number. Just put in the raw number as your answer. For example, 34567.11. But remember you have to specify if the work is positive or negative, if it is negative, you need to input, for example, -34567.11. W Theta T
Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 72.0 kg, down a theta= 51.6° slope at constant acceleration a=-2.5 m/s², as shown in Figure (here we assume the positive direction is going down the slope. So the given acceleration is a negative value, it means its direction is going up the slope, slowing down as it moving downward). So The coefficient of friction between the sled and the snow is 0.100. How many Joules of work is done by the tension in the rope as the sled moves 2.6 m along the hill? Use g= 10 m/s². Your answer for this problem maybe some large number. Just put in the raw number as your answer. For example, 34567.11. But remember you have to specify if the work is positive or negative, if it is negative, you need to input, for example, -34567.11. W Theta T
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 72.0 kg, down a
theta= 51.6° slope at constant acceleration a=-2.5 m/s², as shown in Figure (here we assume the
positive direction is going down the slope. So the given acceleration is a negative value, it means
its direction is going up the slope, slowing down as it moving downward). So The coefficient of
friction between the sled and the snow is 0.100. How many Joules of work is done by the tension
in the rope as the sled moves 2.6 m along the hill? Use g= 10 m/s². Your answer for this problem
maybe some large number. Just put in the raw number as your answer. For example, 34567.11. But
remember you have to specify if the work is positive or negative, if it is negative, you need to input,
for example, -34567.11.
W
Theta
T
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