Suppose the mean weight of a lime is 6.3 oz with a standard deviation of 0.95 oz. (a) Find the probability that a randomly chosen lime weighs less than 7.2 oz. 0.0711 0.5005 0.7269 0.8289 (b) Find the probability that a randomly chosen lime weighs more than 4.8 oz. 0.0152 0.6172 0.7613 0.9429 (c) Find the probability that a randomly chosen lime weighs between 5.7 and 7.2 oz. 0.1448 0.4253 0.5646 0.7225

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
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Suppose the mean weight of a lime is 6.3 oz with a standard deviation of 0.95 oz.
(a) Find the probability that a randomly chosen lime weighs less than 7.2 oz.
0.0711
0.5005
0.7269
0.8289
(b) Find the probability that a randomly chosen lime weighs more than 4.8 oz.
O 0.0152
0.6172
0.7613
0.9429
(c) Find the probability that a randomly chosen lime weighs between 5.7 and 7.2 oz.
0.1448
0.4253
0.5646
0.7225
(d) Find the probability that a sample of 68 randomly chosen limes has a mean weight less than 6.3 oz.
0.2433
0.5
0.6383
0.6493
Transcribed Image Text:Suppose the mean weight of a lime is 6.3 oz with a standard deviation of 0.95 oz. (a) Find the probability that a randomly chosen lime weighs less than 7.2 oz. 0.0711 0.5005 0.7269 0.8289 (b) Find the probability that a randomly chosen lime weighs more than 4.8 oz. O 0.0152 0.6172 0.7613 0.9429 (c) Find the probability that a randomly chosen lime weighs between 5.7 and 7.2 oz. 0.1448 0.4253 0.5646 0.7225 (d) Find the probability that a sample of 68 randomly chosen limes has a mean weight less than 6.3 oz. 0.2433 0.5 0.6383 0.6493
Expert Solution
Step 1: Determine the given data

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From the provided information,

text Mean end text open parentheses mu close parentheses equals 6.3
text Standard deviation end text open parentheses sigma close parentheses equals 0.95
X tilde N left parenthesis 6.3 comma 0.95 right parenthesis

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