Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 250 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers? 0.0427 0.0302 0.0247 0.0349 0.0270
Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 250 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers? 0.0427 0.0302 0.0247 0.0349 0.0270
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Sampling Distribution and Standard Error Calculation Example**
---
**Problem Description:**
Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 250 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers?
**Answer Options:**
- \( \circ \) 0.0427
- \( \circ \) 0.0302
- \( \circ \) 0.0247
- \( \circ \) 0.0349
- \( \circ \) 0.0270
---
**Explanation:**
To find the standard error (SE) for the sampling distribution of the sample proportion, we use the following formula:
\[ \text{SE} = \sqrt{\frac{p(1-p)}{n}} \]
where:
- \( p \) is the population proportion (0.24 in this case)
- \( n \) is the sample size (250 in this case)
Plugging in the values:
\[ \text{SE} = \sqrt{\frac{0.24 \times (1 - 0.24)}{250}} \]
\[ \text{SE} = \sqrt{\frac{0.24 \times 0.76}{250}} \]
\[ \text{SE} = \sqrt{\frac{0.1824}{250}} \]
\[ \text{SE} = \sqrt{0.0007296} \]
\[ \text{SE} \approx 0.0270 \]
Therefore, the standard error for the sampling distribution of the sample proportion of tea drinkers is approximately 0.0270.
The correct answer is:
- \( \circ \) 0.0270
---
This calculation helps understand how much variability can be expected in the sample proportion due to sampling error when repeated samples are taken from the same population.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5018757-df34-47e5-8789-7c8e64b31b6d%2F9c75d7d0-d966-447d-bd2a-454e32348c90%2F6u5hu29_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Sampling Distribution and Standard Error Calculation Example**
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**Problem Description:**
Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 250 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers?
**Answer Options:**
- \( \circ \) 0.0427
- \( \circ \) 0.0302
- \( \circ \) 0.0247
- \( \circ \) 0.0349
- \( \circ \) 0.0270
---
**Explanation:**
To find the standard error (SE) for the sampling distribution of the sample proportion, we use the following formula:
\[ \text{SE} = \sqrt{\frac{p(1-p)}{n}} \]
where:
- \( p \) is the population proportion (0.24 in this case)
- \( n \) is the sample size (250 in this case)
Plugging in the values:
\[ \text{SE} = \sqrt{\frac{0.24 \times (1 - 0.24)}{250}} \]
\[ \text{SE} = \sqrt{\frac{0.24 \times 0.76}{250}} \]
\[ \text{SE} = \sqrt{\frac{0.1824}{250}} \]
\[ \text{SE} = \sqrt{0.0007296} \]
\[ \text{SE} \approx 0.0270 \]
Therefore, the standard error for the sampling distribution of the sample proportion of tea drinkers is approximately 0.0270.
The correct answer is:
- \( \circ \) 0.0270
---
This calculation helps understand how much variability can be expected in the sample proportion due to sampling error when repeated samples are taken from the same population.
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