Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 250 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers? 0.0427 0.0302 0.0247 0.0349 0.0270

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**Sampling Distribution and Standard Error Calculation Example**

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**Problem Description:**

Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 250 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers?

**Answer Options:**

- \( \circ \) 0.0427
- \( \circ \) 0.0302
- \( \circ \) 0.0247
- \( \circ \) 0.0349
- \( \circ \) 0.0270

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**Explanation:**

To find the standard error (SE) for the sampling distribution of the sample proportion, we use the following formula:

\[ \text{SE} = \sqrt{\frac{p(1-p)}{n}} \]

where:
- \( p \) is the population proportion (0.24 in this case)
- \( n \) is the sample size (250 in this case)

Plugging in the values:

\[ \text{SE} = \sqrt{\frac{0.24 \times (1 - 0.24)}{250}} \]
\[ \text{SE} = \sqrt{\frac{0.24 \times 0.76}{250}} \]
\[ \text{SE} = \sqrt{\frac{0.1824}{250}} \]
\[ \text{SE} = \sqrt{0.0007296} \]
\[ \text{SE} \approx 0.0270 \]

Therefore, the standard error for the sampling distribution of the sample proportion of tea drinkers is approximately 0.0270.

The correct answer is:
- \( \circ \) 0.0270

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This calculation helps understand how much variability can be expected in the sample proportion due to sampling error when repeated samples are taken from the same population.
Transcribed Image Text:**Sampling Distribution and Standard Error Calculation Example** --- **Problem Description:** Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 250 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers? **Answer Options:** - \( \circ \) 0.0427 - \( \circ \) 0.0302 - \( \circ \) 0.0247 - \( \circ \) 0.0349 - \( \circ \) 0.0270 --- **Explanation:** To find the standard error (SE) for the sampling distribution of the sample proportion, we use the following formula: \[ \text{SE} = \sqrt{\frac{p(1-p)}{n}} \] where: - \( p \) is the population proportion (0.24 in this case) - \( n \) is the sample size (250 in this case) Plugging in the values: \[ \text{SE} = \sqrt{\frac{0.24 \times (1 - 0.24)}{250}} \] \[ \text{SE} = \sqrt{\frac{0.24 \times 0.76}{250}} \] \[ \text{SE} = \sqrt{\frac{0.1824}{250}} \] \[ \text{SE} = \sqrt{0.0007296} \] \[ \text{SE} \approx 0.0270 \] Therefore, the standard error for the sampling distribution of the sample proportion of tea drinkers is approximately 0.0270. The correct answer is: - \( \circ \) 0.0270 --- This calculation helps understand how much variability can be expected in the sample proportion due to sampling error when repeated samples are taken from the same population.
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