Suppose the line tangent to the graph of f at x = 4 is y= 2x + 1 and suppose y = 5x – 3 is the line tangent to the graph of g at x = 4. Find the line tangent to the following curves at x = 4. a. y = f(x)g(x) f(x) b. y= g(x) The equation of the line tangent to the curve y = f(x)g(x) at x = 4 is y = f(x) at x = 4 is y = g(x) The equation of the line tangent to the curve y =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Title: Finding the Line Tangent to Combined Curves**

**Introduction:**
Understanding how to determine the line tangent to different types of curves at a specific point is an essential concept in calculus. In this lesson, we will explore how to find the line tangents to combined curves at a given point.

**Problem Statement:**
Suppose the line tangent to the graph of \( f \) at \( x = 4 \) is \( y = 2x + 1 \), and the line tangent to the graph of \( g \) at \( x = 4 \) is \( y = 5x - 3 \). We need to find the line tangent to the following curves at \( x = 4 \):

a. \( y = f(x)g(x) \)

b. \( y = \frac{f(x)}{g(x)} \)

**Formulas and Calculations:**
To solve this problem, we need to apply the derivative rules for product and quotient functions. Let's denote \( f(4) \) and \( g(4) \) as the values of the functions at \( x = 4 \).

1. The derivative of a product \( y = f(x)g(x) \):
\[ y' = f'(x)g(x) + f(x)g'(x) \]

2. The derivative of a quotient \( y = \frac{f(x)}{g(x)} \):
\[ y' = \frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2} \]

Given:
- \( f'(4) = 2 \) (slope from the tangent line \( y = 2x + 1 \))
- \( g'(4) = 5 \) (slope from the tangent line \( y = 5x - 3 \))

We apply the above rules at \( x = 4 \).

**Results:**

- The equation of the line tangent to the curve \( y = f(x)g(x) \) at \( x = 4 \) is:
\[ y = [\frac{d}{dx} (f(x)g(x))]_{x=4} \]

- The equation of the line tangent to the curve \( y = \frac{f(x)}{g(x)} \) at \( x = 4 \) is:
Transcribed Image Text:**Title: Finding the Line Tangent to Combined Curves** **Introduction:** Understanding how to determine the line tangent to different types of curves at a specific point is an essential concept in calculus. In this lesson, we will explore how to find the line tangents to combined curves at a given point. **Problem Statement:** Suppose the line tangent to the graph of \( f \) at \( x = 4 \) is \( y = 2x + 1 \), and the line tangent to the graph of \( g \) at \( x = 4 \) is \( y = 5x - 3 \). We need to find the line tangent to the following curves at \( x = 4 \): a. \( y = f(x)g(x) \) b. \( y = \frac{f(x)}{g(x)} \) **Formulas and Calculations:** To solve this problem, we need to apply the derivative rules for product and quotient functions. Let's denote \( f(4) \) and \( g(4) \) as the values of the functions at \( x = 4 \). 1. The derivative of a product \( y = f(x)g(x) \): \[ y' = f'(x)g(x) + f(x)g'(x) \] 2. The derivative of a quotient \( y = \frac{f(x)}{g(x)} \): \[ y' = \frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2} \] Given: - \( f'(4) = 2 \) (slope from the tangent line \( y = 2x + 1 \)) - \( g'(4) = 5 \) (slope from the tangent line \( y = 5x - 3 \)) We apply the above rules at \( x = 4 \). **Results:** - The equation of the line tangent to the curve \( y = f(x)g(x) \) at \( x = 4 \) is: \[ y = [\frac{d}{dx} (f(x)g(x))]_{x=4} \] - The equation of the line tangent to the curve \( y = \frac{f(x)}{g(x)} \) at \( x = 4 \) is:
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