Suppose the life of a particular brand of calculator battery is approximately normally distributed with a mean of 75 hours and a standard deviation of 9 hours. Complete parts a through c a. What is the probability that a single battery randomly selected from the population will have a life between 70 and 80 hours? P(70 sxs80) = 0.4246 (Round to four decimal places as needed.) b. What is the probability that 4 randomly sampled batteries from the population will have a sample mean life of between 70 and 80 hours? P(70sxs80) 0.7335 (Round to four decimal places as needed.) c. If the manufacturer of the battery is able to reduce the standard deviation of battery life from sto 8 hours, what would be the probability that 4 batteries randomly sampled from the population will have a sample mean ife of between 70 and 80 hours? P(70 sxs 80) - (Round to four decimal places as needed.)

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