Suppose the Humane Society claims that 30% of U.S. households own cats. You believe your community isdifferent than the U.S. percentage. To test the claim, you take a simple random sample of 300 householdsand find that 33% own cats. Test at 5% significance.Round to the fourthHo: PHA: PHow many successes were there? 111 XTest Statistic: 2.646 XP-value: 0.995 XDid something significant happen? Nothing Significant HappenedSelect the Decision Rule: Fail to Reject the NullorThere is noto enough evidence to concludethat the proportion of households that own cats in your community is different than the national proportion. V‡0.300.30✔ O

According to the given information in this question We need to answer all the parts

Answered: Suppose the Humane Society claims that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose you take a sample of 25 Reese's pieces. The proportion of orange is 0.4. What is the p-value when testing the hypothesis that the actual proportion of orange for all Reese's pieces is 0.5? Round to two places.
how do i solve for parts b, d, and e?
why are we using the number of events=19 for the sample proportion part of the equation, instead of the actual sample proportion=0.19?
A study compared the felt intensity of unrequited love among three groups - individuals who were currently experiencing unrequited love, those who had previously experienced unrequited love and described their experiences retrospectively, and those who had never experienced unrequited love but described how they thought they would feel if they were to experience it. The results of the study are summarized in the accompanying table. Determine the significance of the difference among groups, using the 5% level. N 40 40 40 M 3.5 3.3 3.7 S2 5.3 5.8 4.8 1. What is th null hyp? 2.The comparison distribution will be an F distribution with df= ? and df=? 3.Determine the cutoff sample score on the comparison distribution at which the null hypothesis should be rejected for the data. At 0.05 the cutoff for F=? 4. Determine the sample's score on the comparison distribution for the data. F=?
If the p-value of a test is .037 then you would
Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 475 randomly selected adults showed that 57% of them would erase all of their personal information online if they could. Find the value of the test statistic.
A random sample of employees participating in a company fitness program were asked how many days they logged an exercise activity in the past month. Their responses are reported in the histogram below.Based on the histogram above, what is the class width? Clas width = ? Days What is the sample size? Sample size = ? employees
According to a report on consumer fraud and identity theft, 20% of all complaints for a year were for identity theft. In that year, Rhode Island had 717 complaints of identity theft out of 3498 consumer complaints. Does this data provide enough evidence to show that Rhode Island had a higher proportion of identity theft than 20%? Test at the 5% level. State the hypotheses. Họ: p ? Ha: P Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .05, reject Ho. O Since the p-value is greater than .05, fail to reject Hg. O Since the p-value is less than .05, fail to reject Hg. O Since the p-value is greater than .05, reject Ho. Interpret the results. O At the 5% level of significance, there is enough evidence to show that the proportion of complaints due to identity theft in Rhode Island is more than…
Statistics Canada conducts an annual survey to estimate the proportion of Canadians aged 20 - 24 years of age who are smokers. The most recent application of the Canadian Tobacco Monitoring Survey involved a random sample of n=496 Canadians aged 20 to 24 years of age. Each was asked for the smoking status. The number of 20 to 24 year-olds sampled who indicated they were smokers was 333.(a) Compute the sample proportion. Use at least four decimals in your answer.p^= __________ (b) Using your answer in (a), find a 97% confidence interval for pnow, the current proportion of 20 to 24 year old Canadians who are smokers, by Bootstrapping 1000 samples. Use the seed 3994 to ensure that R-Studio "randomly" samples the same "random" samples as this question will expect.You can do this by including the code, you can copy it into your R-Studio to bootstrap your samples.RNGkind(sample.kind = "Rejection");set.seed(3994);B=do(1000) * mean(resample(c(rep(1,333),rep(0,496-333)), 496));Use at least four…
The sample mean is the point estimator of O A. u О В. р O C. X O D. o

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