Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean value 19.0 kips and standard deviation 1.50 kips. Compute the following probabilities by standardizing and then using a standard normalcurve table from the Appendix Tables or SALT. (Round your answers to four decimal places.)(a) P(X ≤ 19)(b) P(X ≤ 20.5)(c) P(X2 11.5)USE SALT(d) P(17 ≤ x ≤ 22)(e) P(|X19| ≤ 2)

Answered: Suppose the force acting on a column…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Please answer all bits
i need help with c
Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a random variable that represents the number of milligrams of porphyrin per deciliter of blood. In healthy circles, x is approximately normally distributed with mean μμ = 41 and standard deviation σσ = 16. Find the following probabilities. (Round your answers to four decimal places.)a.) x is less than 60 b.) x is greater than 16 c.) x is between 16 and 60 d.) x is more than 60 (This may indicate an infection, anemia, or another type of illness.)
The level of nitrogen oxides (NOX) and nonmethane organic gas (NMOG) in the exhaust over the useful life (150,000150,000 miles of driving) of cars of a particular model varies Normally with mean 8080 mg/mi and standard deviation 66 mg/mi. A company has 1616 cars of this model in its fleet. Using Table A, find the level ?L such that the probability that the average NOX + NMOG level ?¯x¯ for the fleet greater than ?L is only 0.030.03 ? (Enter your answer rounded to three decimal places. If you are using CrunchIt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision settings.)
I need the answer as soon as possible
Show full answers and steps to this exercise Please don’t use R or excel formula to calculate E(X) and variance. Use normal formula to get to the numbers
Use the data in the Excel workbook, on the worksheet labeled "Sample," for this question. The first column is just an observation index labeled i to name each observation. The observations are a simple random sample with replacement from a much larger population. The second column contains specific values y of a random variable Y found in some sampled population. The population standard deviation is not known to you, but it is known that Y has a Normal distribution in the sampled population. Compute the lower bound of an 85% confidence interval for the population mean of the random variable Y. i y 1 37 2 40 3 31 4 27 5 23 6 33 7 29 8 26 9 39 10 28 11 34 12 39 13 31 14 34 15 39 16 33 17 31 18 42
Q1.2 Mean of X A medical practice collects data on its patients with respect to several personal habits. The following table gives the distribution of the number of alcoholic drinks consumed per day in that population of patients. X = # of drinks per day Probability Save Answer Q1.3 Variance of X X = # of drinks per day Probability 0 0.38 Find the mean for this random variable, that is find ux. Show your work in the space below. Save Answer A medical practice collects data on its patients with respect to several personal habits. The following table gives the distribution of the number of alcoholic drinks consumed per day in that population of patients. 0 0.38 Q1.4 Standard Deviation of X X = # of drinks per day Probability 1 0.32 0 0.38 1 0.32 2 0.25 Find the variance for this random variable, that is find (ox)². Only show the first and last term of the work required. 1 2 0.25 A medical practice collects data on its patients with respect to several personal habits. The following table…
Answer the attached
A snack company makes packages of grapes and honeydew slices. The weight of an individual package of grapes, G, is approximately Normally distributed with a mean of 3.25 ounces and a standard deviation of 0.91 ounces. The weight of an individual package of honeydew slices, H, is approximately Normally distributed with a mean of 4.51 ounces and a standard deviation of 2.02 ounces. Assume G and H are independent random variables. Let D = G – H. What is the probability that a randomly selected package of grapes weighs more than a randomly selected package of honeydew slices? 0.127 0.230 0.284 0.334
Show full answers and steps to this exercise
A random sample of size 10 yielded roughly "mound-shaped" data with a sample mean of 63.5 and a sample variance of 60.8. Let (L, OU) be the interval estimate that contains the population mean with 95% probability. Find the width of the interval. That is, find 0 – 0₁. 4.52 5.49 5.58 5.70 9.04 10.99 11.16 11.40 none of the other answers give the correct width

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS