Finish the C++ code. Suppose the file nums.txt contains the following data: ### Problem Description:Suppose the file `nums.txt` contains the following data:```15 9 -11 22 -7 -18 21 20 -19 12```### Suppose `main()` looks like this:```cppint matrix[2][5];ifstream in;int num;in.open("nums.txt");for (int x = 0; x < 2; x++) { for (int y = 0; y < 5; y++) { in >> num; if (num % 2 == 1) { matrix[x][y] = num / 2 + 4; } else { matrix[x][y] = 3 * (num - 1); } }}```The task is to fill out the following table with the values in the array named `matrix` after the code runs.Remember that row and column indexes begin with 0.### Given Data:```15 9 -11 22 -7 -18 21 20 -19 12```### Explanation of the Code:1. **Read the Data**: The code reads integers from the file `nums.txt` and processes them into a 2x5 matrix named `matrix`.2. **Condition Check**: - If the number is odd (`num % 2 == 1`), it calculates `num / 2 + 4` and stores it in the current matrix cell. - If the number is even, it calculates `3 * (num - 1)` and stores the value in the current matrix cell.### Matrix After Code Execution:We'll apply the conditions to process each number and fill in the matrix:#### Row 1:- `15` (odd): `15 / 2 + 4 = 7 + 4 = 11`- `9` (odd): `9 / 2 + 4 = 4 + 4 = 8`- `-11` (odd): `-11 / 2 + 4 = -5 + 4 = -1`- `22` (even): `3 * (22 - 1) = 3 * 21 = 63`- `-7` (odd): `-7 / 2 + 4 = -3 + 4 =

In the given code simply reading each element from the file into num variable if(num%2==1) means…

Suppose the file nums.txt contains the following data: 15 9 -11 22 -7 -18 21 20 -19 12 Suppose main() looks like this: int matrix[2] [5]; ifstream in; int num; in.open ("nums.txt"); for (int x = 0; x < 2; x++) { for (int y = 0; y < 5; y++) { in >> num; if (num % 2 == 1) { matrix[x] [y] = num / 2 + 4; ) else { matrix[x] [y] = 3 * (num - 1); Fill out the following table with the values in the array named matrix after the code runs. Remember that row and column indexes begin with 0.

Suppose the file nums.txt contains the following data: 15 9 -11 22 -7 -18 21 20 -19 12 Suppose main() looks like this: int matrix[2] [5]; ifstream in; int num; in.open ("nums.txt"); for (int x = 0; x < 2; x++) { for (int y = 0; y < 5; y++) { in >> num; if (num % 2 == 1) { matrix[x] [y] = num / 2 + 4; ) else { matrix[x] [y] = 3 * (num - 1); Fill out the following table with the values in the array named matrix after the code runs. Remember that row and column indexes begin with 0.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Finish the C++ code. Suppose the file nums.txt contains the following data:

### Problem Description:
Suppose the file `nums.txt` contains the following data:
```
15 9 -11 22 -7 -18 21 20 -19 12
```

### Suppose `main()` looks like this:
```cpp
int matrix[2][5];
ifstream in;
int num;
in.open("nums.txt");

for (int x = 0; x < 2; x++) {
for (int y = 0; y < 5; y++) {
in >> num;
if (num % 2 == 1) {
matrix[x][y] = num / 2 + 4;
} else {
matrix[x][y] = 3 * (num - 1);
}
}
}
```

The task is to fill out the following table with the values in the array named `matrix` after the code runs.
Remember that row and column indexes begin with 0.

### Given Data:
```
15 9 -11 22 -7 -18 21 20 -19 12
```

### Explanation of the Code:
1. **Read the Data**: The code reads integers from the file `nums.txt` and processes them into a 2x5 matrix named `matrix`.
2. **Condition Check**:
- If the number is odd (`num % 2 == 1`), it calculates `num / 2 + 4` and stores it in the current matrix cell.
- If the number is even, it calculates `3 * (num - 1)` and stores the value in the current matrix cell.

### Matrix After Code Execution:
We'll apply the conditions to process each number and fill in the matrix:

#### Row 1:
- `15` (odd): `15 / 2 + 4 = 7 + 4 = 11`
- `9` (odd): `9 / 2 + 4 = 4 + 4 = 8`
- `-11` (odd): `-11 / 2 + 4 = -5 + 4 = -1`
- `22` (even): `3 * (22 - 1) = 3 * 21 = 63`
- `-7` (odd): `-7 / 2 + 4 = -3 + 4 =

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