Suppose the equation below models the height h(t) of a distress flare signal at time t seconds. Assume the interval under consideration is [0, 49] where 49 seconds is the time the flare fizzles out and hits the ground. h (t) = -16t² +656t+6272 The Mean Value Theorem guarantees the existence of some value t from 0 to 49 seconds when the instantaneous velocity of the flare is equal to the average velocity. Find this value.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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**Topic: Application of the Mean Value Theorem in Kinematics**

Suppose the equation below models the height \( h(t) \) of a distress flare signal at time \( t \) seconds. Assume the interval under consideration is \([0, 49]\) where 49 seconds is the time the flare fizzles out and hits the ground.

\[ 
h(t) = -16t^2 + 656t + 6272 
\]

The Mean Value Theorem guarantees the existence of some value \( t \) from 0 to 49 seconds when the instantaneous velocity of the flare is equal to the average velocity. Find this value.

**Analysis:**

- **Equation Explanation**: The quadratic equation \( h(t) = -16t^2 + 656t + 6272 \) represents the height of the flare over time.
- **Interval**: The model considers the time from 0 to 49 seconds, with 49 seconds marking the end of the flare’s flight.

**Concept Application**:

- **Mean Value Theorem**: This theorem states that for a continuous function over an interval \([a, b]\), there exists at least one point \( c \) in the interval where the instantaneous rate of change (derivative) is equal to the average rate of change over \([a, b]\).

To apply the theorem, find:

1. The average velocity of the flare over the interval \([0, 49]\).
2. The instantaneous velocity as given by the derivative \( h'(t) \).
3. Solve for the time \( t \) when these two velocities are equal.

**Graphs or Diagrams**: None in the provided content. The focus is on understanding the equation and application of the Mean Value Theorem in kinematics.
Transcribed Image Text:**Topic: Application of the Mean Value Theorem in Kinematics** Suppose the equation below models the height \( h(t) \) of a distress flare signal at time \( t \) seconds. Assume the interval under consideration is \([0, 49]\) where 49 seconds is the time the flare fizzles out and hits the ground. \[ h(t) = -16t^2 + 656t + 6272 \] The Mean Value Theorem guarantees the existence of some value \( t \) from 0 to 49 seconds when the instantaneous velocity of the flare is equal to the average velocity. Find this value. **Analysis:** - **Equation Explanation**: The quadratic equation \( h(t) = -16t^2 + 656t + 6272 \) represents the height of the flare over time. - **Interval**: The model considers the time from 0 to 49 seconds, with 49 seconds marking the end of the flare’s flight. **Concept Application**: - **Mean Value Theorem**: This theorem states that for a continuous function over an interval \([a, b]\), there exists at least one point \( c \) in the interval where the instantaneous rate of change (derivative) is equal to the average rate of change over \([a, b]\). To apply the theorem, find: 1. The average velocity of the flare over the interval \([0, 49]\). 2. The instantaneous velocity as given by the derivative \( h'(t) \). 3. Solve for the time \( t \) when these two velocities are equal. **Graphs or Diagrams**: None in the provided content. The focus is on understanding the equation and application of the Mean Value Theorem in kinematics.
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