Suppose the diameter of a type of atom is 2.22 x 10-7 mm. A coin has diameter 1.20 cm. Suppose the atoms are aligned, touching, side by side,along the diameter of this coin. How many atoms would be needed to do this?Hint: you need to divide the diameter of the coin by the diameter of an atom. But you need to convert your units first!O 6.34 x 10 24 atomsO 1.30 x 10 3 atomsO 5.41 x 10 7 atomsO 9.53 x 10 19 atomsO 6.81 x 10 30 atomsO 5.06 x 10 14 atomsO 8.50 x 10 11 atomsO 7.44 x 10 10 atoms

If we divide the diameter of a coin by the diameter of an atom we will get the no. of atoms. Given…

Suppose the diameter of a type of atom is 2.22 x 10-7 mm. A coin has diameter 1.20 cm. Suppose the atoms are aligned, touching, side by side, along the diameter of this coin. How many atoms would be needed to do this?

Suppose the diameter of a type of atom is 2.22 x 10-7 mm. A coin has diameter 1.20 cm. Suppose the atoms are aligned, touching, side by side, along the diameter of this coin. How many atoms would be needed to do this?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Suppose the diameter of a type of atom is 2.22 x 10-7 mm. A coin has diameter 1.20 cm. Suppose the atoms are aligned, touching, side by side,
along the diameter of this coin. How many atoms would be needed to do this?
Hint: you need to divide the diameter of the coin by the diameter of an atom. But you need to convert your units first!
O 6.34 x 10 24 atoms
O 1.30 x 10 3 atoms
O 5.41 x 10 7 atoms
O 9.53 x 10 19 atoms
O 6.81 x 10 30 atoms
O 5.06 x 10 14 atoms
O 8.50 x 10 11 atoms
O 7.44 x 10 10 atoms

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