Suppose the derivative of a function fis given below. On what interval is f increasing? f(x)=(x+3)(x-4)³(x - 5)8 Part 1 of 4 For any value of x, the squared term (x+3)6 is always positive Part 2 of 4 For any value of x, the fourth-power term (x - 5)8 is always positive ✔ positive positivel Part 3 of 4 Therefore, the sign of the product (x+3)(x-4)³(x-5)=f(x) depends only on the sign of (x-4)³. If x <[ Submit Skip (you cannot come back) , then (x-4)3 is --Select-- , and so the sign of (x+3)(x-4)³(x - 5) = f'(x) is --Select--. Therefore, f(x) is --Select--- -Select-- decreasing

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Suppose the derivative of a function fis given below. On what interval is f increasing?
f'(x) = (x+3)(x-4)³(x - 5)8
Part 1 of 4
For any value of x, the squared term (x+3)6 is always positive ✔
Part 2 of 4
For any value of x, the fourth-power term (x - 5)8 is always positive
positive.
Submit Skip (you cannot come back)
positive
Part 3 of 4
Therefore, the sign of the product (x + 3)(x − 4)³(x − 5)² = f'(x) depends only on the sign of (x-4)³. If x <
then (x-4)³ is---Select---
, and so the sign of (x+3)(x-4)³(x – 5)8 = f'(x) is ---Select---
Therefore, f(x) is
--Select--- ✓
-Select---
decreasing
increasing
Transcribed Image Text:Tutorial Exercise Suppose the derivative of a function fis given below. On what interval is f increasing? f'(x) = (x+3)(x-4)³(x - 5)8 Part 1 of 4 For any value of x, the squared term (x+3)6 is always positive ✔ Part 2 of 4 For any value of x, the fourth-power term (x - 5)8 is always positive positive. Submit Skip (you cannot come back) positive Part 3 of 4 Therefore, the sign of the product (x + 3)(x − 4)³(x − 5)² = f'(x) depends only on the sign of (x-4)³. If x < then (x-4)³ is---Select--- , and so the sign of (x+3)(x-4)³(x – 5)8 = f'(x) is ---Select--- Therefore, f(x) is --Select--- ✓ -Select--- decreasing increasing
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