Suppose the derivative of a function fis given below. On what interval is f increasing? f(x)=(x+3)(x-4)³(x - 5)8 Part 1 of 4 For any value of x, the squared term (x+3)6 is always positive Part 2 of 4 For any value of x, the fourth-power term (x - 5)8 is always positive ✔ positive positivel Part 3 of 4 Therefore, the sign of the product (x+3)(x-4)³(x-5)=f(x) depends only on the sign of (x-4)³. If x <[ Submit Skip (you cannot come back) , then (x-4)3 is --Select-- , and so the sign of (x+3)(x-4)³(x - 5) = f'(x) is --Select--. Therefore, f(x) is --Select--- -Select-- decreasing
Suppose the derivative of a function fis given below. On what interval is f increasing? f(x)=(x+3)(x-4)³(x - 5)8 Part 1 of 4 For any value of x, the squared term (x+3)6 is always positive Part 2 of 4 For any value of x, the fourth-power term (x - 5)8 is always positive ✔ positive positivel Part 3 of 4 Therefore, the sign of the product (x+3)(x-4)³(x-5)=f(x) depends only on the sign of (x-4)³. If x <[ Submit Skip (you cannot come back) , then (x-4)3 is --Select-- , and so the sign of (x+3)(x-4)³(x - 5) = f'(x) is --Select--. Therefore, f(x) is --Select--- -Select-- decreasing
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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