Suppose the cost c of producing qa units of product A and qg units of product B is given by c=(3q°A +q°8 +4) and the coupled demand functions for the products are given by = 10 - PA +p°8 and qg = 12 + PA - 9Pg. Use a chain rule to evaluate and when pPA = 25 and Pe = 4. dPA (Simplify your answer.) OPA PA = 25. Pe -4
Suppose the cost c of producing qa units of product A and qg units of product B is given by c=(3q°A +q°8 +4) and the coupled demand functions for the products are given by = 10 - PA +p°8 and qg = 12 + PA - 9Pg. Use a chain rule to evaluate and when pPA = 25 and Pe = 4. dPA (Simplify your answer.) OPA PA = 25. Pe -4
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Suppose the cost c of producing qA units of product A and qg units of product B is given by c = {39°A + q°8+4)
and the coupled demand functions for the
products are given by qa = 10 - PA +p°B and qg = 12 + PA - 9Pg. Use a chain rule to evaluate
dc
and
= 25 and Pe
when
PA
=4.
dc
(Simplify your answer.)
OPA PA = 25, PB = 4

Transcribed Image Text:For the functions w 5x2 + 6y", x = cos t, and y = sin t, express
dw
as a function of t, both by using the chain rule and by expressing w in terms of t and
dt
dw
differentiating directly with respect to t. Then evaluate at t= -
dt
Express
dw
as a function of t.
dw
dt
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