Suppose that z = x/y, where x and y are differentiable functions of u and v such that x = dx/dv 3, у %3D 1, Әх/әи = 4, дх/дv — — 1, and дy/дv — — 2 when и — 2 —2, ду/ди -2 when u = and ν - 1. When u = 2 and v = 1, Әz/ди and az/av = dz dz

Suppose that z = x/y, where x and y are differentiable functions of u and v such that x = dx/dv 3, у %3D 1, Әх/әи = 4, дх/дv — — 1, and дy/дv — — 2 when и — 2 —2, ду/ди -2 when u = and ν - 1. When u = 2 and v = 1, Әz/ди and az/av = dz dz

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter6: The Trigonometric Functions

Section6.6: Additional Trigonometric Graphs

Problem 78E

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Question

Provide a correct or I swear, I will give negative remarks. I was always provided with the wrong answers here.

Suppose that z = x/y, where x and y are differentiable
functions of u and v such that x =
dx/dv
3, у %3D 1, Әх/әи
= 4,
дх/дv — — 1, and дy/дv — — 2 when и — 2
—2, ду/ди
-2 when u =
and ν -
1. When u =
2 and v =
1, Әz/ди
and
az/av =
dz
dz

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