Suppose that you want to solve the following quadratic formula in Julia: x = −b ± √(b2 − 4ac) / 2a Where: a = the coefficient in front of or the number beside x2 b = the coefficient in front of or the number beside x c = the constant Write a Julia functional program to generate the solutions for a quadratic solution like this one: Where: a = 2, b = -1, c = -1 and solutions for this equation will be 1 and – 1⁄2.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Suppose that you want to solve the following quadratic formula in Julia:

x = −b ± √(b2 − 4ac) / 2a Where:

a = the coefficient in front of or the number beside x2 b = the coefficient in front of or the number beside x c = the constant

Write a Julia functional program to generate the solutions for a quadratic solution like this one:

Where:
a = 2, b = -1, c = -1
and solutions for this equation will be 1 and – 1⁄2.

Expert Solution
Step 1: Algorithm to solve quadratic equation:
  1. Input the coefficients:

    • Read the values of coefficients a, b, and c from the user or another source.
  2. Calculate the discriminant (D):

    • Calculate the discriminant using the formula D = b^2 - 4ac.
  3. Check the discriminant:

    • If the discriminant D is negative, there are no real solutions. Exit the algorithm.
    • If D is zero, there is one real solution:
      • Calculate x = -b / (2a).
      • Output the solution x.
    • If D is positive, there are two real solutions:
      • Calculate x1 = (-b + √D) / (2a) and x2 = (-b - √D) / (2a).
      • Output the solutions x1 and x2.
  4. Output the solutions:

    • If D is negative, output a message indicating no real solutions.
    • If D is zero, output the single solution.
    • If D is positive, output both solutions.


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