Suppose that you want to solve the following quadratic formula in Julia: x = −b ± √(b2 − 4ac) / 2a Where: a = the coefficient in front of or the number beside x2 b = the coefficient in front of or the number beside x c = the constant Write a Julia functional program to generate the solutions for a quadratic solution like this one: Where: a = 2, b = -1, c = -1 and solutions for this equation will be 1 and – 1⁄2.
Suppose that you want to solve the following quadratic formula in Julia: x = −b ± √(b2 − 4ac) / 2a Where: a = the coefficient in front of or the number beside x2 b = the coefficient in front of or the number beside x c = the constant Write a Julia functional program to generate the solutions for a quadratic solution like this one: Where: a = 2, b = -1, c = -1 and solutions for this equation will be 1 and – 1⁄2.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Suppose that you want to solve the following quadratic formula in Julia:
x = −b ± √(b2 − 4ac) / 2a Where:
a = the coefficient in front of or the number beside x2 b = the coefficient in front of or the number beside x c = the constant
Write a Julia functional program to generate the solutions for a quadratic solution like this one:
Where:
a = 2, b = -1, c = -1
and solutions for this equation will be 1 and – 1⁄2.
Expert Solution
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Step 1: Algorithm to solve quadratic equation:
Input the coefficients:
- Read the values of coefficients a, b, and c from the user or another source.
Calculate the discriminant (D):
- Calculate the discriminant using the formula D = b^2 - 4ac.
Check the discriminant:
- If the discriminant D is negative, there are no real solutions. Exit the algorithm.
- If D is zero, there is one real solution:
- Calculate x = -b / (2a).
- Output the solution x.
- If D is positive, there are two real solutions:
- Calculate x1 = (-b + √D) / (2a) and x2 = (-b - √D) / (2a).
- Output the solutions x1 and x2.
Output the solutions:
- If D is negative, output a message indicating no real solutions.
- If D is zero, output the single solution.
- If D is positive, output both solutions.
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