Suppose that you insert the string key "F" into the following linear-probing hash table (with no resizing): key hash(key) 0 1 3 4. 15 A 5 5 keys [] A 4 F Which of the following elementary operations will occur? Mark all that apply. hash("A") hash("B"). hash("D") hash("F") Okeys(41.equals ("F") keys[5).equals("F") keys(6),equale( F")
Suppose that you insert the string key "F" into the following linear-probing hash table (with no resizing): key hash(key) 0 1 3 4. 15 A 5 5 keys [] A 4 F Which of the following elementary operations will occur? Mark all that apply. hash("A") hash("B"). hash("D") hash("F") Okeys(41.equals ("F") keys[5).equals("F") keys(6),equale( F")
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![### Linear-Probing Hash Table Example
#### Problem Statement
Suppose that you insert the string key `"F"` into the following linear-probing hash table (with no resizing):
#### Current Hash Table State
- **Keys Array:**
- Index 0: `C`
- Index 1: `E`
- Index 2: (empty)
- Index 3: (empty)
- Index 4: `D`
- Index 5: `A`
- Index 6: `B`
- Index 7: (empty)
- **Hash Function Information:**
| Key | hash(key) |
|-----|-----------|
| A | 5 |
| B | 5 |
| C | 0 |
| D | 4 |
| E | 0 |
| F | 5 |
#### Question
Which of the following elementary operations will occur?
**Mark all that apply:**
- [ ] `hash("A")`
- [ ] `hash("B")`
- [ ] `hash("D")`
- [ ] `hash("F")`
- [ ] `keys[4].equals("F")`
- [ ] `keys[5].equals("F")`
- [ ] `keys[6].equals("F")`
This exercise involves understanding how linear probing resolves collisions in hash tables by checking each index starting from the hash value until an empty slot is found.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88167701-6d3f-46b8-9f75-5ab21a2347bf%2F59b88a57-970c-415f-aeb0-c31692d927b3%2F22ux9pb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Linear-Probing Hash Table Example
#### Problem Statement
Suppose that you insert the string key `"F"` into the following linear-probing hash table (with no resizing):
#### Current Hash Table State
- **Keys Array:**
- Index 0: `C`
- Index 1: `E`
- Index 2: (empty)
- Index 3: (empty)
- Index 4: `D`
- Index 5: `A`
- Index 6: `B`
- Index 7: (empty)
- **Hash Function Information:**
| Key | hash(key) |
|-----|-----------|
| A | 5 |
| B | 5 |
| C | 0 |
| D | 4 |
| E | 0 |
| F | 5 |
#### Question
Which of the following elementary operations will occur?
**Mark all that apply:**
- [ ] `hash("A")`
- [ ] `hash("B")`
- [ ] `hash("D")`
- [ ] `hash("F")`
- [ ] `keys[4].equals("F")`
- [ ] `keys[5].equals("F")`
- [ ] `keys[6].equals("F")`
This exercise involves understanding how linear probing resolves collisions in hash tables by checking each index starting from the hash value until an empty slot is found.
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