Suppose that y varies directly with x, and y3D12 when x=15. (a) Write a direct variation equation that relates x and y. Equation: (b) Find y when x = 2. y = 0

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Suppose that \( y \) varies directly with \( x \), and \( y = 12 \) when \( x = 15 \).

**(a) Write a direct variation equation that relates \( x \) and \( y \).**

Equation: \[ y = kx \]

**(b) Find \( y \) when \( x = 2 \).**

\[ y = \]

Direct variation means that as one variable increases, the other increases proportionally. The constant \( k \) can be found using the formula \( y = kx \). Given \( y = 12 \) when \( x = 15 \), solve for \( k \) and then use it to find \( y \) when \( x = 2 \).
Transcribed Image Text:Suppose that \( y \) varies directly with \( x \), and \( y = 12 \) when \( x = 15 \). **(a) Write a direct variation equation that relates \( x \) and \( y \).** Equation: \[ y = kx \] **(b) Find \( y \) when \( x = 2 \).** \[ y = \] Direct variation means that as one variable increases, the other increases proportionally. The constant \( k \) can be found using the formula \( y = kx \). Given \( y = 12 \) when \( x = 15 \), solve for \( k \) and then use it to find \( y \) when \( x = 2 \).
### Understanding Force, Mass, and Acceleration

When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. Consider the following scenario:

A certain constant force acts upon an object with a mass of 14 kg, and the acceleration of the object is 2 m/s². When the same force is applied to another object, its acceleration is 7 m/s². What is the mass of this object?

**Interactive Solution Box:**

- Input field: to enter the calculated mass in kilograms (kg).

**Action Buttons:**

- \( \times \) : Clear input.
- \( \checkmark \) : Confirm and check the answer.
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**Navigation:**

- **Check**: To validate the answer.
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- © 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy

This exercise helps in understanding the relationship between force, mass, and acceleration, as governed by Newton's Second Law of Motion.
Transcribed Image Text:### Understanding Force, Mass, and Acceleration When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. Consider the following scenario: A certain constant force acts upon an object with a mass of 14 kg, and the acceleration of the object is 2 m/s². When the same force is applied to another object, its acceleration is 7 m/s². What is the mass of this object? **Interactive Solution Box:** - Input field: to enter the calculated mass in kilograms (kg). **Action Buttons:** - \( \times \) : Clear input. - \( \checkmark \) : Confirm and check the answer. - \( \ ? \ \): Hint or help option. **Navigation:** - **Check**: To validate the answer. - **Save For Later**: To save the progress for later review. - **Submit Assignment**: To submit the answer once complete. **Copyright Information:** - © 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy This exercise helps in understanding the relationship between force, mass, and acceleration, as governed by Newton's Second Law of Motion.
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