Suppose that X, Y, and Z are jointly distributed random variables, that is, they are defined on the same sample spaceSuppose that we also have the following.E(X)=-8E(Y)=6E (Z) = -1Var (X)=33Var(Y)=25 Var(Z) = 48Compute the values of the expressions below.E(-4+3Y) =(2x-2)=0Var(-Y+5)=EE(-5X²) = 0ExplanationWCheck3e00X$55533y8Ⓒ2022 McGraw Hill LLC. All Rights!u

Given that E(X)=-8E(Y)=6E(Z)=-1Var(X)=33Var(Y)=25Var(Z)=48

Answered: Suppose that X, Y, and 2 are jointly…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q10. The probability model for a random variable A is [% ,a=-1 P₁(a)=% a=1 0, otherwise The conditional probability model for random variable B is: %,b=0 P (b/-1)=% .b=1 0, otherwise P (b/1)=,b=1 0, otherwise a) What is the probability model for random variables A and B If 4-1, what is the conditional expected value E[BA-11? c) If B-1, what is the conditional PMF Pa (at)? b) d) If B-1, what is the conditional variance Var [4| B=1]? 110 marke
A biased die is thrown thirty times and the number sixes seen is eight. If the die is thrown a further twelve times find the expected numbers of sixes and the variance of the number of sixes. E(X)=3.2 E(X)=3.1 E(X)=3.3 None of the choices
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An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of “heads” (h) and “tails” (t) which we write hth, ttt, etc. for each outcome let R be the random variable counting the number of heads in each outcome. For example, if the outcome is hhh, then R (hhh)=3. Suppose that the random variable X is defined in terms of R as follows: X= 2R-2R^2-3. The values of X are given in the table below.
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Please explain your answer with steps Suppose X and Y are random variables such that E[X] = -3 and E[Y] = 6. Then E[X-Y] equals: Suppose that X and Y are random variables such that E[X] = -2and E[Y] = 4. Then E[-X] equals: Suppose that X and Y are random variables such that E[X] = -1 and E[Y] = 2. Then the random variable 2X+Y must be always equal to zero not necessarily always equal to zero and has an unknown expected value not necessarily always equal to zero but has an expected value equal to zero 2X + Y is not a random variable Suppose X is a random variable such that Var(X) = 2. Then Var(-X) equals Suppose X is a random variable such that Var(X) = 1. Then Var(4X) equals Suppose X is a random variable such that Var(X) = 1. Then Var(X+2) equals
Q6. For two random variables X and Y, fxy(x, y) = 0.5 8(x+1) &(y)+0.1 8(x) 8{y) + 0.1 8(x) 8(y-2) + 0.4 &(x-1) S(y+2) + 0.2 &x– 1) d(y – 1) + 0.5 8(x – 1) 8(y – 3). Find, (a) The correlation
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is ttt, then N (ttt) = 0. Suppose that the random variable X is defined in terms of N as follows: X = 2N−2N2 - 1. The values of X are given in the table below. Outcome ttt hht tth htt hhh tht hth thh Value of X −1 −5 −1 −1 −13 −1 −5 −5 Calculate the probabilities P (X = x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X P (X = x)
Suppose that X, Y, and Z are jointly distributed random variables, that is, they are defined on the same sample space. Suppose that we also have the following. E(X)=-9 E (Z) = 1 E (Y)=-6 Var(Y)=28 Var(Z) = 47 Var (X)=44 Compute the values of the expressions below. E (2-Z) = 0 E(X+32)=0 -5 -2-Var(4X) = 0 E(-x²) = 0 Continue □ X S M 31 Ⓒ2022 McGraw Hill LLC. All Rights Reserved
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2. Let X be a binomial random variable with E(X) = 30 and Var(X) = 21. Find the parameters n and p of X.
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (1) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is htt, then N (htt) = 1. Suppose that the random variable X is defined in terms of N as follows: X=2N-N2 -4, The values of X are given in the table below. Outcome hht tth hth thh tht ttt hhh htt Value of x -4 -3 -4 -4 -3 -4 -7 -3 Calculate the probabilities P(X=*) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value of x _ _ _ p(X=x) _ _ _

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