Suppose that we use Euler's method to approximate the solution to the differential equation n 0 1 2 3 4 5 dy Xn 0.3 uit Let f(x, y) = x²/y. We let co= 0.3 and yo = 8 and pick a step size h = 0.2. Euler's method is the the following algorithm. From an and yn, our approximations to the solution of the differential equation at the nth stage, we find the next stage by computing Xn+1 = xn+h, f(xn, yn). Complete the following table. Your answers should be accurate to at least seven decimal places. X Y ; y(0.3) = 8. Yn+1=Yn+h. Yn 8 The exact solution can also be found using separation of variables. It is y\it) = Thus the actual value of the function at the point x = 1.3 y(1.3) =
Suppose that we use Euler's method to approximate the solution to the differential equation n 0 1 2 3 4 5 dy Xn 0.3 uit Let f(x, y) = x²/y. We let co= 0.3 and yo = 8 and pick a step size h = 0.2. Euler's method is the the following algorithm. From an and yn, our approximations to the solution of the differential equation at the nth stage, we find the next stage by computing Xn+1 = xn+h, f(xn, yn). Complete the following table. Your answers should be accurate to at least seven decimal places. X Y ; y(0.3) = 8. Yn+1=Yn+h. Yn 8 The exact solution can also be found using separation of variables. It is y\it) = Thus the actual value of the function at the point x = 1.3 y(1.3) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Suppose that we use Euler's method to approximate the
solution to the differential equation
Let f(x, y)
We let xo
n
0
1
2
3
= x² /y.
0.3 and yo = 8 and pick a step size h = 0.2.
Euler's method is the the following algorithm. From an and
yn, our approximations to the solution of the differential
equation at the nth stage, we find the next stage by
computing
xn+1 = xn+h, Yn+1 = Yn + h. f(xn, yn).
Complete the following table. Your answers should be
accurate to at least seven decimal places.
4
5
dy
Xn
0.3
ax
Y
;
y(0.3) = 8.
Yn
8
The exact solution can also be found using separation of
variables. It is
y\it) =
Thus the actual value of the function at the point x = 1.3
y(1.3) =
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