Suppose that we use Euler's method to approximate the solution to the differential equation 25 dy dx The exact solution can also be found using separation of variables. It is y(x) = y Thus the actual value of the function at the point x = 1.1 y(1.1) = S Let f(x, y) = x³/y. We let zo = 0.1 and yo = 6 and pick a step size h = 0.2. Euler's method is the the following algorithm. From an and yn, our approximations to the solution of the differential equation at the nth stage, we find the next stage by computing y(0.1) = 6. Xn+1 = xn+h, Complete the following table. Your answers should be accurate to at least seven decimal places. n In Yn 0 0.1 6 |1| 2 3 4 Yn+1 = Yn+h. f(xn, yn).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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Suppose that we use Euler's method to approximate the solution to the differential equation
dy
dr
Let f(x, y) = x³/y.
We let x = 0.1 and yo = 6 and pick a step size h = 0.2. Euler's method is the the following algorithm. From an and yn, our approximations to the solution of the differential
equation at the nth stage, we find the next stage by computing
2
3
20
Y
y(0.1) = 6.
Complete the following table. Your answers should be accurate to at least seven decimal places.
n xn Yn
0 0.1 6
The exact solution can also be found using separation of variables. It is
y(x) = 0
Thus the actual value of the function at the point x = 1.1
y(1.1):
n+1 = xn+h, Yn+1 Yn+h. f(xn, yn).
Transcribed Image Text:Suppose that we use Euler's method to approximate the solution to the differential equation dy dr Let f(x, y) = x³/y. We let x = 0.1 and yo = 6 and pick a step size h = 0.2. Euler's method is the the following algorithm. From an and yn, our approximations to the solution of the differential equation at the nth stage, we find the next stage by computing 2 3 20 Y y(0.1) = 6. Complete the following table. Your answers should be accurate to at least seven decimal places. n xn Yn 0 0.1 6 The exact solution can also be found using separation of variables. It is y(x) = 0 Thus the actual value of the function at the point x = 1.1 y(1.1): n+1 = xn+h, Yn+1 Yn+h. f(xn, yn).
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