Suppose that we track the velocity of Prof.Watkins' car within the first 19 seconds it is traveling and we get that v(0)%3D0,v(3) = 50, v(6) = 83, v(8) = 104, v(12) = 131, and v(19) = 161. How far did his car travel in those 19 seconds if we use a right endpoint approximation and assume that the velocity was given in feet per second? OA 377 feet 1200 OB. 1131 feet OC. 931.5 feet 0.25875 feet None of the listed answers

The position of a honeybee flying up and down a straight flowerbed is given by (the euqation ) where t is measured in seconds and s is measured in meters. Positive values of s indicate that the bee is to the right of the center of the flowerbed, while negative values of s indicate that it is to the left of the center. (a) Use the graph to guess the time(s) at which the velocity of the bee is 0, and then use calculus to confirm the answer (b) How fast and in what direction is the bee flying at t = 3.5 seconds?  (c) Find the velocity of the bee at all times when its acceleration is zero.

In the previous Problem Set question, we started looking at the position functions (t), the position of an object at time t. Two important physics concepts are the velocity and the acceleration. If the current position of the object at time is as (t), then the position at time h later is a (t+h). The average velocity (speed) during that additional time his (s(t+h)-s(t)) If we want to analyze the instantaneous velocity at time t, this can be made into a mathematical model by taking the limit as h→0. i.e. the derivative a' (t). Use this function in the model below for the velocity function (). h The acceleration is the rate of change of velocity, so using the same logic, the acceleration function a(t) can be modeled with the derivative of the velocity function, or the second derivative of the position function a(t) = ✔ (t) =" (t). Problem set question: A particle moves according to the position functions (t) = etsin (2). Enclose arguments of functions in parentheses. For example, sin…