Suppose that we titrate 100.0 ML of 0.0500 M Fe^+ with 0.100 M Ce^4+, by using the cell and figure 16-1. The equivalence point occurs when Vce^4+ = 50.0ml because the Ce^4+ is twice as concentrated as the Fe^2+. Calculate the cell voltage at 36.0, 50.0 and 63.0ml

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