Suppose that we have a computer system with a logical address space of 4,096 pages with an 8-KB page size, mapped onto a physical memory of 512 frames. How many bits are required in the logical address? *Give your answer in decimal number format.
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Suppose that we have a computer system with a logical address space of 4,096 pages with an 8-KB page size, mapped onto a physical memory of 512 frames. How many bits are required in the logical address?
*Give your answer in decimal number format.
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- Suppose the RAM for a certain computer has 4M words, where each word is 16 bits long. What is the capacity of this memory expressed in bytes? If this RAM is byte addressable, how many bits must an address contain? If this RAM is word addressable, how many bits must an address contain?Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. How many bits are used for the page number? How many bits are used for the offset? With this system, what’s the maximum number of pages that a process can have? Suppose that each entry in the page table comprises 4 bytes (including the frame number, the valid bit, and miscellaneous “bookkeeping bits”). An OS uses an array to store the page table. What is the size of the page table? Furthermore, suppose the first 6 pages of a process map to frames 222 to 227 (as decimal numbers), and the last 5 pages of the process map to frames 1 to 5 (also decimal numbers). All other pages are invalid. Draw the page table, including the valid bit and the frame number.Suppose that we have a computer system with a 18-bit logical address and 4 KB page size. How many entries are there in a page table? *Give your answer in decimal format.
- Given a computer equipped with 67,108,864 bytes of memory with 16-bit cells, how many bits are needed to specify a memory address?Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. How many bits are used for the page number? How many bits are used for the offset? 8 bits each. With this system, what’s the maximum number of pages that a process can have? 256 Suppose that each entry in the page table comprises 4 bytes (including the frame number, the valid bit, and miscellaneous “bookkeeping bits”). An OS uses an array to store the page table. What is the size of the page table? 1024 Bytes Furthermore, suppose the first 6 pages of a process map to frames 222 to 227 (as decimal numbers), and the last 5 pages of the process map to frames 1 to 5 (also decimal numbers). All other pages are invalid. Draw the page table, including the valid bit and the frame number. DONE Translate the following virtual addresses to physical addresses, and show how you obtain the answers. (Hint: You do not need to convert…What is the maximum number of 16-bit words that can be stored in a 2^32 byte physical memory?
- Given a virtual memory of size 4 GiB, physical memory of size 512 KiB, and page size equal to 4 KiB. How many bits are used to specify a physical page number?Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. Supposed also that each block contains 16 bytes. The size of the offset field is 19 bits and the size of the block field is 0.625 bytes.Assuming a 4-KB page size (4096 bytes), what are the page numbers and offsets for the following address references (provided as decimal numbers); assume that the memory is byte addressable. a. 3000 b. 40000 c. 200000 d. 6000000
- Addressing Memory Suppose that there are 226 bytes in memory. In binary the lowest address is 00...00, and the highest address is 11...11. a. What is the lowest address (in decimal) if memory is byte addressable? b. What is the highest address (in decimal) if memory is byte addressable? c. Suppose that a word is 16-bits long. What is the lowest address (in decimal) if memory is word addressable? d. Suppose that a word is 16-bits long. What is the highest address (in decimal) if memory is word addressable? e. Suppose that a word is 32-bits long. What is the lowest address (in decimal) if memory is word addressable? f. Suppose that a word is 32-bits long. What is the highest address (in decimal) if memory is word addressable?In a microcomputer, the addresses of memory locations are binary numbers that identify each memory circuit where a byte is stored. The number of bits that make up an address depends on how many memory locations there are. Since the number of bits can be very large, the addresses are often specified in hex instead of binary. If a microcomputer uses a 24-bit address, how many different memory locations are there? What is the largest number that can be How many hex digits are needed to represent the address of a memory location? What is the hex address of the 172th memory location? (Note: The first address is always ) The computer program is stored in the lowest 3 kbyte block of memory. Give the start and end address of this What is the BCD code of the hex address of the 172th memory location?Consider the following table that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): ADDRESS OxFFFF OXOCOE OXOCOD Ox0C0C OXOCOB OXOCOA 0x0C09 0x0000 CONTENTS 1111 1111 1111 1111 1111 1110 1101 1100 0001 1011 1100 0101 0110 0101 1000 0111 1100 0000 0100 0000 0011 0001 0101 0010 0000 1100 0000 1101 0000 0000 0000 0000 The table above shows the addresses in hex (base 16) and the contents at the corresponding address in binary (base 2). A.) What are the contents in hex of the memory location at following address in binary: 0000 1100 0000 1110? (Enter hex like the following example: Ox2A3F)
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