Suppose that we define the function g as follows: g(x) = 8x + 9 whenever x is not equal to 3 and g(3) = 20. It is clear that the limit of g(x), as x approaches 3, is 33. Let € = 0.01 . In other words, in this problem we are given that epsilon is 0.01. Find the maximum allowable numerical value of d that satisfies the following: If x is in the interval (3-d, 3+d) and x is not equal to 3, then g(x) will be in the interval (33-0.01, 33+0.01). Type the exact answer as a decimal in the answer box below. The maximum allowable numerical value for d is:
Suppose that we define the function g as follows: g(x) = 8x + 9 whenever x is not equal to 3 and g(3) = 20. It is clear that the limit of g(x), as x approaches 3, is 33. Let € = 0.01 . In other words, in this problem we are given that epsilon is 0.01. Find the maximum allowable numerical value of d that satisfies the following: If x is in the interval (3-d, 3+d) and x is not equal to 3, then g(x) will be in the interval (33-0.01, 33+0.01). Type the exact answer as a decimal in the answer box below. The maximum allowable numerical value for d is:
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 99E: Determine if the statemment is true or false. If the statement is false, then correct it and make it...
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Suppose that we define the function g as follows: g(x) = 8x + 9 whenever x is not equal to 3 and g(3) = 20. It is
clear that the limit of g(x), as x approaches 3, is 33. Let € = 0.01 . In other words, in this problem we are given
that epsilon is 0.01. Find the maximum allowable numerical value of d that satisfies the following:
If x is in the interval (3-d, 3+d) and x is not equal to 3, then g(x) will be in the interval (33-0.01, 33+0.01).
Type the exact answer as a decimal in the answer box below.
The maximum allowable numerical value for d is:
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