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- One cable company claims that it has excellent customer service. In fact, the company advertises that a technician will arrive within 55 minutes after a service call is placed. One frustrated customer believes this is not accurate, claiming that it takes over 55 minutes for the cable technician to arrive. The customer asks a simple random sample of 4 other cable customers how long it has taken for the cable technician to arrive when they have called for one. The sample mean for this group is 62.1 minutes with a standard deviation of 8.3 minutes. Assume that the population distribution is approximately normal. Test the customer’s claim at the 0.05 level of significance. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.12)A crossover trial is a type of experiment used to compare two drugs. Subjects take one drug for a period of time, then switch to the other. The responses of the subjects are then compared using matched-pair methods. In an experiment to compare two pain relievers, seven subjects took one pain reliever for two weeks, then switched to the other. They rated their pain level from 1 to 10, with larger numbers representing higher levels of pain. The results are listed below. Can you conclude that the mean pain level is more with drug B? Use the 0.05 level and the P-value method. Subject 1 2 3 5 3 4 5 6 7 2 5 2 6 Drug A 1 1 Drug B 3 7 (c) State the appropriate null and alternate hypotheses. (d) Compute the P-value. e) State a conclusion. 6 5 6 6 (c) Determine whether to reject Null Hypothesis. 13disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Now suppose you are an auditor for a very large corporation. The revenue report involves millions of numbers in a large computer file. Let us say you took a random sample of n = 223 numerical entries from the file and r = 48 of the entries had a first nonzero digit of 1. Let p represent the population proportion of all numbers in the corporate file that have a first nonzero digit of 1.(i) Test the claim that p is less than 0.301. Use ? = 0.05. (a) What is the level of significance?State the null and alternate hypotheses. H0: p < 0.301; H1: p = 0.301H0: p = 0.301; H1: p > 0.301 H0: p = 0.301; H1: p < 0.301H0: p = 0.301; H1: p ≠ 0.301 (b) What sampling distribution will you use? The standard normal, since np > 5 and nq > 5. The standard normal, since np < 5 and nq <…
- True or False: Suppose I conducted a study using random assignment. This suggests that I took great effort to ensure that all of my subjects had an equal chance of being in either group.2. In a population it is estimated that 20% have a desired trait of interest for the researcher. The researcher wants to know how many people on average he has to draw from a population to get 2 people with the trait. Use rows 20-24 of the Random Number Table to carry out the simulation. Explain clearly how you set up the problem and report your findings. Answer:2. Some scientists believe that the presence of antibody to milk protein lowers the chance of survival after a heart attack. To explore this belief, a medical team took blood specimens from 335 male heart-attack patients and tested them for the presence of the antibody. The patients were then followed to determine whether they lived for 6 months following their heart attack. The results are presented in Table 2. Suppose we want to answer the following question: "Test, at the 5% level of significance, whether there is an association between the presence of antibody to milk protein and survival after a heart attack." Table 2: Survival vs Antibody to Milk Protein contingency table Survival Antibody to Milk Protein Alive Died Total Present 24 52 76 Absent 126 133 259 Total 150 185 335 SPSS produced the information needed to perform the hypothesis test in Table 3. Table 3: Chi-Square Tests Results Chi-Square Tests Asymptotic Significance (2-sided) Exact Sig. (2- sided) Exact Sig. (1- sided)…
- An airline operates a call center to handle customer questions and complaints. The airline monitors a sample of calls to help ensure that the service being provided is of high quality. Ten random samples of 100 calls each were monitored under normal conditions. The center can be thought of as being in control when these 10 samples were taken. The number of calls in each sample not resulting in a satisfactory resolution for the customer is as follows. 4 5 3 2 3 3 46 4 8 (a) What is an estimate of the proportion of calls not resulting in a satisfactory outcome for the customer when the center i in control? 0.0042 (b) Construct the upper and lower limits for a p chart for the manufacturing process, assuming each sample has 100 calls. (Round your answers to four decimal places.) UCL = 0.0655 LCL = 0.0558 (c) With the results of part (b), what conclusion should be made if a sample of 100 has 13 calls not resulting in a satisfactory resolution for the customer? Since the sample proportion =…A dowser has correctly located water for a well 1 out of 2 times in Jones County. In Jones County, someone who is just guessing has a 40% chance of locating water for a well. Does this sample provide sufficient evidence that the dowser can locate water and is not just guessing?Identify the correct null hypothesis (from the below choices) for each: 1. A study wished to see if husbands or wives are more satisfied in their marriage. They selected 100 married couples and asked both the husband and wives to rate their satisfaction on a scale of 1 to 10. [Select] 2. A study wished to see if husbands or wives are more satisfied in their marriage. They selected a 100 married men and 100 married women and asked them rate their satisfaction on a scale of 1 to 10. [Select] 3. A study wished to see if husbands or wives are more satisfied in their marriage. From a previous study the average score (from 1 to 10) of wives was 6.5. They selected a sample of 100 married men and asked them to rate their satisfaction on a scale of 1 to 10. [Select]
- is described below. NOTE: If the method is experimental, indicate if it is a true experiment or quasi experiment. 1. I get 30 people and use random assignment to divide the people into two groups. One group reads an article about the statistics of injuries and deaths caused by people using smart phones while driving, the other group watches a short video about a person who killed someone while using their smart phone. Both groups are then monitored to see if either of these made a difference in how often these people use their smart phones use while behind the wheel. What method would that study be? 2. What method asks a series of questions that are all planned in advance?6) Any basketball fan knows that Shaquille O’Neal, one of the NBA’s most dominant centers of the last twenty years, always had difficulty shooting free throws. Over the course of his career, his overall made free-throw percentage was 53.3%. During one off-season, Shaq had been working with an assistant coach on his free-throw technique. During the next season, a simple random sample showed that Shaq made 26 of 39 free-throw attempts. Test the claim that Shaq has significantly improved his free-throw shooting using a 0.05 significance level. Check the conditions of the Central Limit Theorem for this scenario. Calculate the number of failures.