Suppose that two arrays X₁, X2, ..., Xn and y₁, y2, Yn have at least one element in common. The following algorithm finds i, j such that x; = y;. Compute its best-case and worst-case complexity. (Count the number of # comparisons.) i 0 j+n+1 while j=n+ 1 do rii+1 Yn+1 Xi ← j←1 while xi #yj do j+j+1

Suppose that two arrays X₁, X2, ..., Xn and y₁, y2, Yn have at least one element in common. The following algorithm finds i, j such that x; = y;. Compute its best-case and worst-case complexity. (Count the number of # comparisons.) i 0 j+n+1 while j=n+ 1 do rii+1 Yn+1 Xi ← j←1 while xi #yj do j+j+1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Counting sort

The counting sort algorithm sorts an array’s contents by counting the repetition of each element that occurs in the array. A counting sort algorithm is a stable algorithm that works the best when the range of elements in the array is small, say for example from 0 to 9. The count which is the number of repetitions of an element in the array is mapped to an index of an auxiliary array, which is then saved in an auxiliary array. The counting sort algorithm has a stable time complexity of the order of O(size of array + size of auxiliary array). Let’s discuss the algorithm in detail as follows.

Question

Suppose that two arraysx1,x2,…,xnandy1,y2,…,yn.( Need only handwritten solution please otherwise downvote).

Suppose that two arrays X₁, X2,
Xn and y1, y2,
Yn have at least one element in common. The
following algorithm finds i, j such that x;= y;. Compute its best-case and worst-case complexity.
(Count the number of comparisons.)
i - 0
j+n+1
while j=n+ 1 do
rii+1
Yn+1 Xi
j+1
L
...
while xi #yj do
j←j+1

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