Suppose that there are 22 crayons in a box: 6 green crayons, 8 blue crayons, and 8 red crayons. Once a crayon is drawn from the box, it is not returned to the box. Enter all answers in the form of a fraction. a. What is the probability of choosing a red crayon, then a blue crayon? P(red) = P(blue | red) P(red then blue) = = b. What is the probability of choosing 2 green crayons in a row? P(green) = P(green | green) = P(green then green) ||

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Suppose that there are 22 crayons in a box: 6 green crayons, 8 blue crayons, and 8 red crayons. Once a crayon is drawn from the box, it is not returned to the box. Enter all answers in the form of a fraction.

Suppose that there are 22 crayons in a box: 6 green
crayons, 8 blue crayons, and 8 red crayons. Once a
crayon is drawn from the box, it is not returned to
the box. Enter all answers in the form of a fraction.
a. What is the probability of choosing a red crayon,
then a blue crayon?
P(red)
=
P(blue | red)
=
P(red then blue)
P(green) =
b. What is the probability of choosing 2 green
crayons in a row?
=
P(green | green)
=
P(green then green)
=
Transcribed Image Text:Suppose that there are 22 crayons in a box: 6 green crayons, 8 blue crayons, and 8 red crayons. Once a crayon is drawn from the box, it is not returned to the box. Enter all answers in the form of a fraction. a. What is the probability of choosing a red crayon, then a blue crayon? P(red) = P(blue | red) = P(red then blue) P(green) = b. What is the probability of choosing 2 green crayons in a row? = P(green | green) = P(green then green) =
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