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Suppose that the universe were full of spherical objects, each of mass m and radius r . If the objects were distributed uniformly throughout the universe, what number density (#/m3) of spherical objects would be required to make the density equal to the critical density of our Universe? Values:  m = 4 kg r = 0.0407 m Answer must be in scientific notation and include zero decimal places (1 sig fig --- e.g., 1234 should be written as 1*10^3)

Suppose that the universe were full of spherical objects, each of mass m and radius r . If the objects were distributed uniformly throughout the universe, what number density (#/m3) of spherical objects would be required to make the density equal to the critical density of our Universe? Values:  m = 4 kg r = 0.0407 m Answer must be in scientific notation and include zero decimal places (1 sig fig --- e.g., 1234 should be written as 1*10^3)

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Suppose that the universe were full of spherical objects, each of mass m and radius r . If the objects were distributed uniformly throughout the universe, what number density (#/m3) of spherical objects would be required to make the density equal to the critical density of our Universe?

Values: 

m = 4 kg

r = 0.0407 m

Answer must be in scientific notation and include zero decimal places (1 sig fig --- e.g., 1234 should be written as 1*10^3)

 

I don't follow the work and I got the wrong answer, so please help and show your work as I do not follow along easily

thanks

Chrome File Edit View History Bookmarks Profiles Tab Window Help 90% Wed Feb 2 7:31 PM James Ball E b Answered: Suppose that the ur X b My Tutoring | bartleby b Answered: Suppose that the ur X bartleby.com/questions-and-answers/suppose-that-the-universe-were-full-of-spherical-objects-. O J : $/7085b8e9-003c-48c0-8510... 202 217,533 Homework help starts here! & ASK CHAT Vx MATH SOLVER y resources 2 Concept and Principle: now! Critical density is the average density required for the universe to halt its expansion. Such a universe is said to be flat. It is given by, LIVE CHAT 3H? Pc = 8nG Here H is the Hubble constant and G is Newton's gravitational constant. Ds and get a solution in as fast as 30 min Calculation: First, we calculate the critical density. The current value for Hubble's constant is around 73.3 km•s•Mpc. 77x10-26 kg m-34 2 103 3x1022 m³ -kg-1s-2) 3( 73.3x • S Pc = 87(6.674x10-11 W -3 1.0677 x10¬26 kg • m' Now, the number density of balls required will be, kg-m-3 4 kg 1.0677×10¬26 1f170a5 ec-ad3d n = -27 -3 3D 2.66 х10 m -3 n = 2 .66 ×10-27 m Screen Snot 1f170a50-8470-11 2022-02...4.24 AM
Transcribed Image Text:Chrome File Edit View History Bookmarks Profiles Tab Window Help 90% Wed Feb 2 7:31 PM James Ball E b Answered: Suppose that the ur X b My Tutoring | bartleby b Answered: Suppose that the ur X bartleby.com/questions-and-answers/suppose-that-the-universe-were-full-of-spherical-objects-. O J : $/7085b8e9-003c-48c0-8510... 202 217,533 Homework help starts here! & ASK CHAT Vx MATH SOLVER y resources 2 Concept and Principle: now! Critical density is the average density required for the universe to halt its expansion. Such a universe is said to be flat. It is given by, LIVE CHAT 3H? Pc = 8nG Here H is the Hubble constant and G is Newton's gravitational constant. Ds and get a solution in as fast as 30 min Calculation: First, we calculate the critical density. The current value for Hubble's constant is around 73.3 km•s•Mpc. 77x10-26 kg m-34 2 103 3x1022 m³ -kg-1s-2) 3( 73.3x • S Pc = 87(6.674x10-11 W -3 1.0677 x10¬26 kg • m' Now, the number density of balls required will be, kg-m-3 4 kg 1.0677×10¬26 1f170a5 ec-ad3d n = -27 -3 3D 2.66 х10 m -3 n = 2 .66 ×10-27 m Screen Snot 1f170a50-8470-11 2022-02...4.24 AM
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