Suppose that the time between arrivals at a bank is modelled as a Weibull(a, ß=1) distribution, and the prior distribution for a is Gamma( K = 3, 1 = 2). A sample of n=5 arrival times was taken and yielded the following: 0.1768, 2.5927, 2.2854, 1.1068, 3.9493 What is the MAP for a? (Pick the "closest" solution.) O a. 0.6953 O b. 0.9437 O c. 0.8409 O d. 0.9933

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Suppose that the time between arrivals at a bank is modelled as a Weibull(a, ß=1) distribution, and the prior distribution for a is Gamma(
K = 3, 1 = 2). A sample of n=5 arrival times was taken and yielded the following:
0.1768, 2.5927, 2.2854, 1.1068, 3.9493
What is the MAP for a? (Pick the "closest" solution.)
a. 0.6953
O b. 0.9437
O c.
0.8409
O d. 0.9933
Transcribed Image Text:Suppose that the time between arrivals at a bank is modelled as a Weibull(a, ß=1) distribution, and the prior distribution for a is Gamma( K = 3, 1 = 2). A sample of n=5 arrival times was taken and yielded the following: 0.1768, 2.5927, 2.2854, 1.1068, 3.9493 What is the MAP for a? (Pick the "closest" solution.) a. 0.6953 O b. 0.9437 O c. 0.8409 O d. 0.9933
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