Suppose that the results of a peak-hour trip generation analysis for a five-zone small urban area is as follows: Trip Productions: P=11,000 P:-93,300 P=12,900 P-203,500 Ps-90,700 person-trips Trip Attractions: A,=135,800 A;-57,500 A,-80,900 A,-72,000 A;-85,200 person-trips Given the following friection factor matrix (based on travel time and cost factors) as follows: Fy Matrix To zone 2 34 0.78 0.44 0.55 0.28 0.28 From Zone 2 0.44 1.30 0.40 0.70 0.33 0.55 0.40 1.30 0.44 0.80 4 0.28 0.70 0.44 1.80 0.44 5 0.28 0.33 0.80 0.44 1.80 Calculate the expected peak-hour trip distribution from zone 2 to zone 5 (T2s =?).

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Suppose that the results of a peak-hour trip generation analysis for a five-zone small urban area is as follows:
Trip Productions: P=11,000 P:-93,300 P=12,900 P-203,500 Ps-90,700 person-trips
Trip Attractions: A,=135,800 A;-57,500 A,-80,900 A,-72,000 A;-85,200 person-trips
Given the following friection factor matrix (based on travel time and cost factors) as follows:
Fy Matrix
To zone
2 34
0.78
0.44
0.55
0.28
0.28
From Zone
2
0.44
1.30
0.40
0.70
0.33
0.55
0.40
1.30
0.44
0.80
4
0.28
0.70
0.44
1.80
0.44
5
0.28
0.33
0.80
0.44
1.80
Calculate the expected peak-hour trip distribution from zone 2 to zone 5 (T2s =?).
Transcribed Image Text:Suppose that the results of a peak-hour trip generation analysis for a five-zone small urban area is as follows: Trip Productions: P=11,000 P:-93,300 P=12,900 P-203,500 Ps-90,700 person-trips Trip Attractions: A,=135,800 A;-57,500 A,-80,900 A,-72,000 A;-85,200 person-trips Given the following friection factor matrix (based on travel time and cost factors) as follows: Fy Matrix To zone 2 34 0.78 0.44 0.55 0.28 0.28 From Zone 2 0.44 1.30 0.40 0.70 0.33 0.55 0.40 1.30 0.44 0.80 4 0.28 0.70 0.44 1.80 0.44 5 0.28 0.33 0.80 0.44 1.80 Calculate the expected peak-hour trip distribution from zone 2 to zone 5 (T2s =?).
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