Suppose that the proportion of investors who are risk-averse (that is, try to avoid risk in their investmentdecisions) is though to be at least 0.7. A financial advisor believes that the proportion is actually less than 0.7.A survey of 36 investors found that 24 of them were risk-averse. Formulate a one-sample hypothesis test for aproportion to test this belief.Determine the null hypothesis, H,, and the alternative hypothesis, H,.HoH,:(Type integers or decimals. Do not round.)

Answered: Image /qna-images/answer/d624a3ca-69db-4aca-beb5-caf320230cb1.jpg

Answered: Suppose that the proportion of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The 2017 Chapman University Survey of American Fears asked a random sample of 1207 American aduts they believed that alens had come to Earth in modem times, and 20% responded yes. Complete parts (a) through (d) below a What es the standard emor tor ths estmate of the peroentage ot a Amencans who Deeve that aens have come to tam n mooern smes? Round to four decimal places as needed.) b. Find a 90% confidence interval for the proportion of all Americans who believe that alens have come to Earth in modem time (Round to two decimal places as needed.) c. What is the margin of error for the 0% confidence interval S (Round to two decimal places as needed) d Suppose that a similar poll conducted in 2016 found that 24.3% of Americans believed alens have come to Earth in modem imes. Baned on your cortdence interval, can you conclude that the proportion of Americans who believe this has increased sinoe 20107 OA. The interval does not support this claim. This is because 24.3% is not in the…
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
5.A random sample of 362 married couples found that 286 had two or more personality preferences in common. In another random sample of 550 married couples, it was found that only 30 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. Find a 90% confidence interval for p1 – p2. (Use 3 decimal places.) lower limit upper limit
4. on paper. random sample of 130 human body temperatures had a mean 98.25 degree and astandard deviation of 0.73 degree. Construct a 99% confidence interval for the average body temperature ofhealthy people.
For the data set below, calculate r, r2, and a 95 percent confidence interval in r units. Then write a one- to two sentence conclusion statement that includes whether the null hypothesis was rejected or not and whether there is a strong /weak/no relationship. Assume a two tailed hypothesis and α = .05. Case 1 Case 2 Case 3 Case 4 Case 5 Case 6 X 1.05 1.15 1.30 2.00 1.75 1.00 Y 2 2 3 4 5 2
You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 424 randomly selected caterpillars observed, 50 lived to become butterflies. a. With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 424 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
Suppose that the proportion of investors who are risk-averse (that is, try to avoid risk in their investment decisions) is though to be at least 0.6. A financial advisor believes that the proportion is actually less than 0.6. A survey of 30 investors found that 18 of them were risk-averse. Formulate a one-sample hypothesis test for a proportion to test this belief. ..... Determine the null hypothesis, H,, and the alternative hypothesis, H,. 2 0.6 < 0.6 Ho: I H,: I (Type integers or decimals. Do not round.) Compute the test statistic. (Round to two decimal places as needed.)
Suppose that the proportion of investors who are risk-averse (that is, try to avoid risk in their investment decisions) is though to be at least 0.7. A financial advisor believes that the proportion is actually less than 0.7. A survey of 35 investors found that 23 of them were risk-averse. Formulate a one-sample hypothesis test for a proportion to test this belief. Determine the null hypothesis, H,, and the alternative hypothesis, H,. Ho H,: (Type integers or decimals. Do not round.) Compute the test statistic. (Round to two decimal places as needed.) Find the p-value for the test. (Round to three decimal places as needed.) State the conclusion at the 0.05 level of significance. The p-value is V the chosen value of a, so the null hypothesis. There is evidence to conclude that the proportion of investors who are risk-averse is not at least 0.7.
7. use the given confidence interval to find the margin of error and the sample proportion. a. (0.719,0.745) b. (0.753,0.777)
1. Suppose a random sample of 32 National Football League players had an average weight of 252.5 pounds. Assume that the standard deviation for weight of all players in the league is 31 pounds. Determine the margin of error for a 99% confidence interval for this sample.
A study regarding the average cost of online streaming services in two states (A and B) is conducted. The results are shown in the following table. X and Y are independent.
Q.4.1 Construct a 99% confidence interval for the true proportion of all employees ofPeople Plus Pty who believe that they should be given a raise by the company,given that 115 out of a sample of 135 employees support this suggestion.Interpret your answer.

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