00Suppose that the probability that a particular computer chip fails after t= a hours of operation is 0.00002- 0.00002t dt.eaa. Find the probability that the computer chip fails after 19,000 hr of operation (that is, the chip lasts at least 19,000 hr).b. Of the chips that are still in operation after 19,000 hr, what fraction of these will operate for at least another 19,000 hr?00c. Evaluate 0.00002- 0.00002t dt and interpret its meaning.ea. The probability that the chip fails after 19,000 hr of operation is(Round to three decimal places as needed.)b. The fraction that will still be operating for at least another 19,000 hr is(Round to three decimal places as needed.)c. Choose the correct answer below.A. The probability that the chip fails immediately is 0.00002- 0.00002t dt =B. The probability that the chip eventually fails is 0.00002- 0.00002t dt =eC. The probability that the chip never fails is 0.000020.00002t dt =eD. There is not enough information to interpret this interval.

Name: 00Suppose that the probability that a particular computer chip fails
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Description: 00Suppose that the probability that a particular computer chip fails after t= a hours of operation is 0.00002- 0.00002t dt.eaa. Find the probability that the computer chip fails after 19,000 hr of operation (that is, the chip lasts at least 19,000 h

Assume, t be the random variable representing the operational time (in hours) after which a…

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Probability

Suppose that the probability that a particular computer chip fails after t= a hours of operation is 0.00002 - 0.00002t dt. a a. Find the probability that the computer chip fails after 19,000 hr of operation (that is, the chip lasts at least 19,000 hr). b. Of the chips that are still in operation after 19,000 hr, what fraction of these will operate for at least another 19,000 hr? 00 c. Evaluate 0.00002 - 0.00002t dt and interpret its meaning. e

Suppose that the probability that a particular computer chip fails after t= a hours of operation is 0.00002 - 0.00002t dt. a a. Find the probability that the computer chip fails after 19,000 hr of operation (that is, the chip lasts at least 19,000 hr). b. Of the chips that are still in operation after 19,000 hr, what fraction of these will operate for at least another 19,000 hr? 00 c. Evaluate 0.00002 - 0.00002t dt and interpret its meaning. e

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

Topic Video

Question

00
Suppose that the probability that a particular computer chip fails after t= a hours of operation is 0.00002
- 0.00002t dt.
e
a
a. Find the probability that the computer chip fails after 19,000 hr of operation (that is, the chip lasts at least 19,000 hr).
b. Of the chips that are still in operation after 19,000 hr, what fraction of these will operate for at least another 19,000 hr?
00
c. Evaluate 0.00002
- 0.00002t dt and interpret its meaning.
e
a. The probability that the chip fails after 19,000 hr of operation is
(Round to three decimal places as needed.)
b. The fraction that will still be operating for at least another 19,000 hr is
(Round to three decimal places as needed.)
c. Choose the correct answer below.
A. The probability that the chip fails immediately is 0.00002
- 0.00002t dt =
B. The probability that the chip eventually fails is 0.00002
- 0.00002t dt =
e
C. The probability that the chip never fails is 0.00002
0.00002t dt =
e
D. There is not enough information to interpret this interval.

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